Chapter 6, Problem 6.1P

To determine

The distance in travel corresponds to $1$

  $\mu$ sec of time for electromagnetic energy.

Answer to Problem 6.1P

  $299.792M$

Explanation of Solution

Calculation:

We have

  $V=\frac{D}{t}$

Where, V is the velocity of the electromagnetic energy, D is the distance traveled by the electromagnetic energy in time t, and t is the time of the travel.

The velocity of the electromagnetic energy in vacuum is $299,792,458m/\sec$ .

Substitute the values in the equation.

  $\begin{array}{l}D=299,792,458m/s\times 1\mu \sec \\ D=299,792,458m/s\times 1\mu \sec \times \frac{{10}^{-6}\sec }{1\mu \sec }\\ D=299.792m\end{array}$

Conclusion:

Therefore, the distance in travel corresponding to $1$$\mu$ sec of time electromagnetic energy is

  $299.792m$ .