The ground-state electron configuration for the following ion should be determined: Ni 2 + Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively. All the suborbital can have maximum of 2 electrons with opposite spins.

Question

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Answer 1

Question

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

Ni²+

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution: Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

Explanation of Solution

The cation Ni²+ is formed when parent atom Ni loses two electrons. Ni has an atomic number 28, that is, Ni atom has 28 electrons. The electrons configuration of Ni is as follows:

Ni (28): [Ar]3d84 s2

Nickel loses its two 4s electrons to give Ni²+ with the Nickel configuration as follows:

Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

(c)

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

N³-

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Explanation of Solution

The anion N³- is formed when parent atom nitrogen gains three electrons. N has an atomic number 7, that is, N atom has 7 electrons. The electrons configuration of N is as follows:

N(7):1s22s22p3

Nitrogen gains 3 electrons to give N³- with the configuration as follows:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

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Answer 2

Question

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

Ni²+

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution: Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

Explanation of Solution

The cation Ni²+ is formed when parent atom Ni loses two electrons. Ni has an atomic number 28, that is, Ni atom has 28 electrons. The electrons configuration of Ni is as follows:

Ni (28): [Ar]3d84 s2

Nickel loses its two 4s electrons to give Ni²+ with the Nickel configuration as follows:

Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

(c)

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

N³-

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Explanation of Solution

The anion N³- is formed when parent atom nitrogen gains three electrons. N has an atomic number 7, that is, N atom has 7 electrons. The electrons configuration of N is as follows:

N(7):1s22s22p3

Nitrogen gains 3 electrons to give N³- with the configuration as follows:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

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Answer 3

Question

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

Ni²+

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution: Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

Explanation of Solution

The cation Ni²+ is formed when parent atom Ni loses two electrons. Ni has an atomic number 28, that is, Ni atom has 28 electrons. The electrons configuration of Ni is as follows:

Ni (28): [Ar]3d84 s2

Nickel loses its two 4s electrons to give Ni²+ with the Nickel configuration as follows:

Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

(c)

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

N³-

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Explanation of Solution

The anion N³- is formed when parent atom nitrogen gains three electrons. N has an atomic number 7, that is, N atom has 7 electrons. The electrons configuration of N is as follows:

N(7):1s22s22p3

Nitrogen gains 3 electrons to give N³- with the configuration as follows:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

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Answer 4

Question

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

Ni²+

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution: Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

Explanation of Solution

The cation Ni²+ is formed when parent atom Ni loses two electrons. Ni has an atomic number 28, that is, Ni atom has 28 electrons. The electrons configuration of Ni is as follows:

Ni (28): [Ar]3d84 s2

Nickel loses its two 4s electrons to give Ni²+ with the Nickel configuration as follows:

Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

(c)

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

N³-

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Explanation of Solution

The anion N³- is formed when parent atom nitrogen gains three electrons. N has an atomic number 7, that is, N atom has 7 electrons. The electrons configuration of N is as follows:

N(7):1s22s22p3

Nitrogen gains 3 electrons to give N³- with the configuration as follows:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

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Answer 5

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

Ni²+

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution: Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

Explanation of Solution

The cation Ni²+ is formed when parent atom Ni loses two electrons. Ni has an atomic number 28, that is, Ni atom has 28 electrons. The electrons configuration of Ni is as follows:

Ni (28): [Ar]3d84 s2

Nickel loses its two 4s electrons to give Ni²+ with the Nickel configuration as follows:

Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

(c)

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

N³-

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Explanation of Solution

The anion N³- is formed when parent atom nitrogen gains three electrons. N has an atomic number 7, that is, N atom has 7 electrons. The electrons configuration of N is as follows:

N(7):1s22s22p3

Nitrogen gains 3 electrons to give N³- with the configuration as follows:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Answer 6

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

Ni²+

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution: Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

Explanation of Solution

The cation Ni²+ is formed when parent atom Ni loses two electrons. Ni has an atomic number 28, that is, Ni atom has 28 electrons. The electrons configuration of Ni is as follows:

Ni (28): [Ar]3d84 s2

Nickel loses its two 4s electrons to give Ni²+ with the Nickel configuration as follows:

Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

(c)

Answer 7

Chapter 6, Problem 6.1P

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

Ni²+

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Answer 8

Expert Solution

Answer to Problem 6.1P

Solution: Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The cation Ni²+ is formed when parent atom Ni loses two electrons. Ni has an atomic number 28, that is, Ni atom has 28 electrons. The electrons configuration of Ni is as follows:

Ni (28): [Ar]3d84 s2

Nickel loses its two 4s electrons to give Ni²+ with the Nickel configuration as follows:

Ni:[Ar]3d84s2→electron loses−2 electronsNi2+:[Ar]3d8

(c)

Answer 13

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

N³-

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Expert Solution

Answer to Problem 6.1P

Solution:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Explanation of Solution

The anion N³- is formed when parent atom nitrogen gains three electrons. N has an atomic number 7, that is, N atom has 7 electrons. The electrons configuration of N is as follows:

N(7):1s22s22p3

Nitrogen gains 3 electrons to give N³- with the configuration as follows:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Answer 14

Interpretation Introduction

Interpretation:

The ground-state electron configuration for the following ion should be determined:

N³-

Concept introduction: Electronic configuration represents the arrangement of electrons in different orbitals following the rules of filling of electrons in the atomic orbitals such as s orbital can have maximum of two electrons, p orbital can have maximum of 6 electrons and the maximum number of electrons in d and f orbitals are 10 and 14 respectively.

All the suborbital can have maximum of 2 electrons with opposite spins.

Answer 15

Expert Solution

Answer to Problem 6.1P

Solution:

N:1s22s22p3→electron gains+3 electronsN3−1s22s22p6 or Ne

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

The anion N³- is formed when parent atom nitrogen gains three electrons. N has an atomic number 7, that is, N atom has 7 electrons. The electrons configuration of N is as follows:

N(7):1s22s22p3