PRACTICE OF STATS - 1 TERM ACCESS CODE
4th Edition
ISBN: 9781319403348
Author: BALDI
Publisher: Macmillan Higher Education
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Question
Chapter 6, Problem 6.1AYK
To determine
To identify: whether the study in the problem is observational or experimental.
Expert Solution & Answer
Answer to Problem 6.1AYK
The particular study is observational study.
Explanation of Solution
The study aims to determine percentage of adults whose right cerebral hemisphere is larger than left hemisphere. On a group of people aged 20 and older representing American adult population, brain imaging is done. Afterwards each scan is analyzed to decide which part of brain is larger.
The above study is an observational study and not experimental study.
This is because an observational study measures variable of interest (percentage of adults with larger right hemisphere) but does not influence the results. In an experimental study, a particular treatment is applied to a group of people and compared with control group (group where in no treatment is applied).
Here since brain imaging is done for every member without influencing the response, it is not an experimental study.
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In order to find probability, you can use this formula in Microsoft Excel:
The best way to understand and solve these problems is by first drawing a bell curve and marking key points such as x, the mean, and the areas of interest. Once marked on the bell curve, figure out what calculations are needed to find the area of interest.
=NORM.DIST(x, Mean, Standard Dev., TRUE).
When the question mentions “greater than” you may have to subtract your answer from 1.
When the question mentions “between (two values)”, you need to do separate calculation for both values and then subtract their results to get the answer.
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Compute the probability of a value between 44.0 and 55.0.
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If a uniform distribution is defined over the interval from 6 to 10, then answer the followings:
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Chapter 6 Solutions
PRACTICE OF STATS - 1 TERM ACCESS CODE
Ch. 6 - Prob. 6.1AYKCh. 6 - Prob. 6.2AYKCh. 6 - Prob. 6.3AYKCh. 6 - Prob. 6.4AYKCh. 6 - Prob. 6.5AYKCh. 6 - Prob. 6.6AYKCh. 6 - Prob. 6.7AYKCh. 6 - Prob. 6.8AYKCh. 6 - Prob. 6.9AYKCh. 6 - Prob. 6.10AYK
Ch. 6 - Prob. 6.11AYKCh. 6 - Prob. 6.12AYKCh. 6 - Prob. 6.13AYKCh. 6 - Prob. 6.14AYKCh. 6 - Prob. 6.15CYSCh. 6 - Prob. 6.16CYSCh. 6 - Prob. 6.17CYSCh. 6 - Prob. 6.18CYSCh. 6 - Prob. 6.19CYSCh. 6 - Prob. 6.20CYSCh. 6 - Prob. 6.21CYSCh. 6 - Prob. 6.22CYSCh. 6 - Prob. 6.23CYSCh. 6 - Prob. 6.24CYSCh. 6 - Prob. 6.25ECh. 6 - Prob. 6.26ECh. 6 - Prob. 6.27ECh. 6 - Prob. 6.28ECh. 6 - Prob. 6.29ECh. 6 - Prob. 6.30ECh. 6 - Prob. 6.31ECh. 6 - Prob. 6.32ECh. 6 - Prob. 6.33ECh. 6 - Prob. 6.34ECh. 6 - Prob. 6.35ECh. 6 - Prob. 6.36ECh. 6 - Prob. 6.37ECh. 6 - Prob. 6.38ECh. 6 - Prob. 6.39ECh. 6 - Prob. 6.40ECh. 6 - Prob. 6.41ECh. 6 - Prob. 6.42ECh. 6 - Prob. 6.43E
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