Principles of Instrumental Analysis
Principles of Instrumental Analysis
7th Edition
ISBN: 9781337468039
Author: Skoog
Publisher: Cengage
Question
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Chapter 6, Problem 6.15QAP
Interpretation Introduction

(a)

Interpretation:

Given absorbance value should be converted into percent transmittance.

Concept introduction:

Transmittance (T) of a medium is the fraction of incident radiation transmitted by the medium.

T=PPo

Where,

Po = power of incident beam

P = power of transmitted beam

Percent Transmittance (T%) = PPo×100%

The relationship between absorbance ( A ) and Transmittance (T) is as follows;

A =  log(T)

Interpretation Introduction

(b)

Interpretation:

Given absorbance value should be converted into percent transmittance.

Concept introduction:

Transmittance (T) of a medium is the fraction of incident radiation transmitted by the medium.

T=PPo

Where,

Po = power of incident beam

P = power of transmitted beam

Percent Transmittance (T%) = PPo×100%

The relationship between absorbance ( A ) and Transmittance (T) is as follows;

A =  log(T)

Interpretation Introduction

(c)

Interpretation:

Given absorbance value should be converted into percent transmittance.

Concept introduction:

Transmittance (T) of a medium is the fraction of incident radiation transmitted by the medium.

T=PPo

Where,

Po = power of incident beam

P = power of transmitted beam

Percent Transmittance (T%) = PPo×100%

The relationship between absorbance ( A ) and Transmittance (T) is as follows;

A =  log(T)

Interpretation Introduction

(d)

Interpretation:

Given absorbance value should be converted into percent transmittance.

Concept introduction:

Transmittance (T) of a medium is the fraction of incident radiation transmitted by the medium.

T=PPo

Where,

Po = power of incident beam

P = power of transmitted beam

Percent Transmittance (T%) = PPo×100%

The relationship between absorbance ( A ) and Transmittance (T) is as follows;

A =  log(T)

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The emission data in cps displayed in Table 1 is reported to two decimal places by the chemist. However, the instrument output is shown in Table 2. Table 2. Iron emission from ICP-AES Sample Blank Standard Emission, cps 579.503252562 9308340.13122 Unknown Sample 343.232365741 Did the chemist make the correct choice in how they choose to display the data up in Table 1? Choose the best explanation from the choices below. No. Since the instrument calculates 12 digits for all values, they should all be kept and not truncated. Doing so would eliminate significant information. No. Since the instrument calculates 5 decimal places for the standard, all of the values should be limited to the same number. The other decimal places are not significant for the blank and unknown sample. Yes. The way Saman made the standards was limited by the 250-mL volumetric flask. This glassware can report values to 2 decimal places, and this establishes our number of significant figures. Yes. Instrumental data…
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