FUNDAMENTALS OF THERMODYNAMICS
10th Edition
ISBN: 9781119634928
Author: Borgnakke
Publisher: WILEY
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5) A fluid fits the following equation of state.
a= 10-3 m3K/(bar*mol) ve b = 8*10-5 m3/molFor this fluid, the average Cp value between 0-300 0C at 1 bar is 33.5 J / mol.K.a) Calculate the average Cp value in the 0-300 0C temperature range for 12 barpressure.b) Calculate the enthalpy and entropy change when the fluid is brought from 4 bar and300 K to 12 bar and 400 K.
1. Complete the following table. Show the states on the T-v diagram
Substance
T°C
P, KPa
Internal Energy.
Enthalpy,
Specific volume,
Quality, X
Phase description
u, kj/kg
h, kj/kg
v, m'/kg
Pg 98 pa
H,0
200
10000
H,O
600
2000
R-134a
900
180
3.10 For H,O, deterane the specified property at the indi-
cated state. Locate the state on a sketch of the T-v diagram.
(a) p = 300 kPa, v 0.5 m'/kg. Find T, in "C.
(b) p 28 MPa, T 200 C. Find v, in m'/kg.
(c) p 1 MPa, T 405 C. Find e, in m'/kg.
(d) T 100°C,x- 60%. Find v, in m/kg.
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- 3.6 WP For H,0, determine the specified property at the indicated state. a. T = 140°C, v = 0.5 m³/kg. Find p, in bar b. p = 30 MPa, T = 100°C. Find v, in m³/kg. c. p = 10 MPa, T = 485°C. Find v, in m³/kg. d. T = 80°C, x = 0.75. Find p, in bar, and v, in m³/kg.arrow_forwardOne-quarter Ibmol of oxygen gas (O2) undergoes a process from p1 = 20 Ib;/in?, T1 = 500°R to p2 = 150 lbę/in?. For the process W = -500 Btu and Q = -227.5 Btu. Assume the oxygen behaves as an ideal gas. Determine T2, in °R, and the change in entropy, in Btu/°R.arrow_forwardOne-quarter Ibmol of oxygen gas (O2) undergoes a process from P1 = 20 lbf/in?, T1 = 500°R to p2 = 150 lbę/in2. For the process W = -500 Btu and Q = -177.5 Btu. Assume the oxygen behaves as an ideal gas. Determine T2, in °R, and the change in entropy, in Btu/°R.arrow_forward
- Provide complete solution and detailed diagram. A gas has an enthalpy of 2400 KJ/kg and internal energy of 2200 KJ/kg. Find the specificvolume of the gas at 950 Kpa pressure. A. 0.12 m3/kg B. 0.93 m3/kg C. 0.72 m3/kg D. 0.21 m3/kgarrow_forwardQ1: a) If for a given gas (Ou/ov)0, find u, the specific internal energy if c, is constant. b) If the equation of state for the gas in part (a) is given by v-(RT/p) = a, find c,- c, for that gas. c) Show that (@h/op)r=-C, (@T/ôp)n.arrow_forwardIdentify the Enthalpy of State 1 to 4 (h1, h2, h3 and h4)arrow_forward
- A piston cylinder device with stops as shown contains water initially at 25 oC and 100 kPa “State 1”. Heat is then added, and piston moves till it hits the stops where cylinder contains two phase mixture with quality x2 = 0.616 “State 2”. Heating continues until final Pressure is 300 kPa “State 3”. 1) What is the final specific volume (m3/kg)? 1.2217 Not listed 1.1202 1.0440 0.9864 1.0551 2) What is the boundary work (kJ/kg)? 122.07 98.54 Not listed 104.30 116.85 111.92 3) What is the final Temperature (oC)? 457.1 371.1 441.6 408.0 Not listed 522.6arrow_forwardArgon (molar mass 40 kg/kmol) compresses reversibly in an adiabatic system from 5 bar, 25 °C to a volume of 0.2 m If the initial volume occupied was 0.9 m calculate the final pressure in bar to 2 decimal places.. Assume nitrogen to be a perfect gas and take cv 0.3122kJ/kgK. Question 12 of 84 A Moving to another questlon will save this response.arrow_forwardONLY B,C,D ( NEED NEAT HANDWRITTEN SOLUTION ONLY OTHERWISE DOWNVOTE).arrow_forward
- stion 10 A piston cylinder device with stops as shown contains water initially at 25 C and 100 kPa "State 1". Heat is then added, and piston moves till it hits the stops where cylinder contains two phase mixture with quality X=0.616 "State 2". Heating continues until final Pressure is 300 kPa "State 3". rel answered ked out of 6.00 Flag question Piston Piston Qin 1) What is the final specific volume (m°/kg)? O 0.9864 O 1.1202 O 1.0440 O 1.2217 O None of the abovearrow_forward3. Find the internal energy of water at the given states for 6 MPa and determine: T,°C U, KJ/Kg Phase Description saturated vapor State 1 State 2 saturated liquid saturated liquid saturated vapor state 3 + 0.95 state 4 500°C state 5 100°C state 6 T= 460°C a- The internal energy b-and the phase descriptions in the following table for water.arrow_forwardThermodynamicarrow_forward
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What is entropy? - Jeff Phillips; Author: TED-Ed;https://www.youtube.com/watch?v=YM-uykVfq_E;License: Standard youtube license