Explanation Since, phosphorus has five valence electrons and three are used in bond formation. Number of lone pairs can be calculated as follows: n = V .E − B .E 2 Here, n is number of lone pairs, V.E is number of valence electrons and B.E is number of bonding electrons. Since, number of valence electrons and bonding electrons are 5 and 3 respectively, number of lone pair will be: n = 5 − 3 2 = 2 2 = 1 Therefore, there is one lone pair on central atom

Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)

13th Edition

ISBN: 9780134421353

Author: Karen C. Timberlake

Publisher: PEARSON

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Chapter 6, Problem 6.140APP

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To determine: Lewis structure and shape of the molecule.

(a) PH3 (b) HCN

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Chapter 6, Problem 6.139APP

Chapter 6, Problem 6.141APP

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Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)

Ch. 6.1 - State the number of electrons that be must be lost...Ch. 6.1 - State the number of electrons that must be gained...Ch. 6.1 - State the number of electrons lost or gained when...Ch. 6.1 - Prob. 6.4PP Ch. 6.1 - Write the symbols for the ions with the following...Ch. 6.1 - Write the symbols for the ions with the following...Ch. 6.1 - Prob. 6.7PP Ch. 6.1 - State the number of protons and electrons in each...Ch. 6.1 - Write the symbol for the ion of each of the...Ch. 6.1 - Write the symbol for the ion of each of the...

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Lewis structure and shape of the molecule. (a) PH 3 (b) HCN

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To determine: Lewis structure and shape of the molecule. (a) PH3 (b) HCN

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Chapter 6 Solutions

To determine: Lewis structure and shape of the molecule.

(a) PH3 (b) HCN