Chapter 6, Problem 6.124QP

Interpretation Introduction

Interpretation:

The standard enthalpy of formation of Acetone has to be calculated.

Concept introduction:

Standard enthalpy change of reaction:

The standard enthalpy change of reaction is given by

$\begin{array}{l}{\text{ΔH}}^{\text{o}}\text{=}{\displaystyle \sum {\text{nΔH}}_{\text{f}}^{\text{o}}}\left(\text{products}\right)\text{-}{\displaystyle \sum {\text{nΔH}}_{\text{f}}^{\text{o}}}\left(\text{reactants}\right)\\ \text{where,}\\ {\text{ΔH}}^{\text{o}}\text{-}\text{standard}\text{enthalpy}\text{change}\\ {\text{ΔH}}_{\text{f}}^{\text{o}}\text{-}\text{standard}\text{enthalpy}\text{change}\text{of}\text{formation}\end{array}$