Explanation Formula used: For any polynomials a , b , c and d a b ⋅ c d = a c b d , where b , d ≠ 0 . Algebraic identity, ( a 2 − b 2 ) = ( a + b ) ( a − b ) . Calculation: Simplify the provided expression, 4 x 2 − 1 x 2 − 4 ⋅ 2 x 2 + 4 x 4 x + 2 = ( 4 x 2 − 1 ) ( 2 x 2 + 4 x ) ( x 2 − 4 ) ( 4 x + 2 ) = ( ( 2 x ) 2 − 1 2 ) 2 x ( x + 2 ) ( x 2 − 2 2 ) 2 ( 2 x + 1 ) Using the property ( a 2 − b 2 ) = ( a + b ) ( a − b ) in the numerator and the denominator both

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ISBN: 9780134178967

Author: John Tobey Jr., Jeffrey Slater, Jamie Blair, Jenny Crawford

Publisher: PEARSON

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Chapter 6, Problem 5RP

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To calculate: Simplify of the expression 4x2−1x2−4⋅2x2+4x4x+2.

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Chapter 6, Problem 4RP

Chapter 6, Problem 6RP

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Chapter 6 Solutions

Intermediate Algebra (8th Edition)

Ch. 6.1 - Find the domain of each of the following rational...Ch. 6.1 - Find the domain of each of the following rational...Ch. 6.1 - Find the domain of each of the following rational...Ch. 6.1 - Prob. 4E Ch. 6.1 - Simplify completely. − 18 x 4 y 12 x 2 y 6 Ch. 6.1 - Simplify completely. − 7 x y 2 28 x 5 y Ch. 6.1 - Prob. 7E Ch. 6.1 - Simplify completely. 24 x 2 − 4 x 4 x 2 − 8 x Ch. 6.1 - Simplify completely. 8 x 2 28 x 2 + 4 x Ch. 6.1 - Simplify completely. 30 x 2 6 x 2 + 18 x

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Simplify of the expression 4 x 2 − 1 x 2 − 4 ⋅ 2 x 2 + 4 x 4 x + 2 .

Solution Summary: The author explains how to simplify the expression c4x2.

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To calculate: Simplify of the expression 4x2−1x2−4⋅2x2+4x4x+2.

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Chapter 6 Solutions