Explanation Given information: The integral is ∫ t t 2 + 1 d t Calculation: Take ∫ t t 2 + 1 d t (1) Substituting t 2 + 1 = w ⇒ 2 t d t = d w ⇒ t d t = d w 2 Using these in (1), we get ∫ t t 2 + 1 d t = ∫ 1 w

Applied Calculus, 6e WileyPLUS + Loose-leaf

6th Edition

ISBN: 9781119408901

Author: Deborah Hughes-Hallett, Andrew M. Gleason, Patti Frazer Lock, Daniel E. Flath

Publisher: Wiley (WileyPLUS Products)

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Chapter 6, Problem 56SYU

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True or false:

The substitution w=t2+1 converts the integral ∫tt2+1dt into ∫12wdw.

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Chapter 6, Problem 55SYU

Chapter 6, Problem 57SYU

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Chapter 6 Solutions

Applied Calculus, 6e WileyPLUS + Loose-leaf

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True or false: The substitution w = t 2 + 1 converts the integral ∫ t t 2 + 1 d t into ∫ 1 2 w d w .

Solution Summary: The author explains that the substitution of w=t2+1 converts the integral into a value that is true.

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True or false:

The substitution w=t2+1 converts the integral ∫tt2+1dt into ∫12wdw.

Want to see the full answer?

Chapter 6 Solutions

True or false: The substitution w = t 2 + 1 converts the integral ∫ t t 2 + 1 d t into ∫ 1 2 w d w .

Solution Summary: The author explains that the substitution of w=t2+1 converts the integral into a value that is true.

Concept explainers

Videos

True or false: The substitution w=t2+1 converts the integral ∫tt2+1dt into ∫12wdw.

Want to see the full answer?

Chapter 6 Solutions

True or false:

The substitution w=t2+1 converts the integral ∫tt2+1dt into ∫12wdw.