Explanation Given info: Mass of Sam=75kg. Force from the engine of the Jet Ski=200 N Coefficient of frictional force ( μ k ) =0.10 There are two forces acting on the Jet Ski before it run out of the fuel. One is thrust from the engine and the other one is frictional force. According to Newton’s third law of motion normal force of the Jet Ski is equal to the weight of the Jet Ski. n = W = m × g n = ( 75 kg ) ( 9.8 m/s 2 ) = 735 N (I) Now f k = μ k m × g Substituting the value of mg from equation (I) and coefficient of kinetic friction, frictional force is given by f k = (0.10) (735N) = 73.5 N (II) Sum of forces = F (thrust) - Frictional force ( f k ) = 200N-73.5N (forces are acting in the opposite direction, therefore they are subtracted. Also, the direction of friction is always opposite to the direction of motion) =126.5N (III) Acceleration of the Jet Ski is calculated using Newton’s second law of motion To determine (b) Distance travelled before the Jet Ski comes to Stop

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ISBN: 9781323834831

Author: Knight

Publisher: PEARSON C

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Question

Chapter 6, Problem 49EAP

To determine

Top speed of Sam

To determine

(b)

Distance travelled before the Jet Ski comes to Stop

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Chapter 6, Problem 48EAP

Chapter 6, Problem 50EAP

Chapter 6 Solutions

PHYS 212 FOR SCI+ENG W/MAST PHYS >ICP<

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