Introduction To Chemistry
Introduction To Chemistry
5th Edition
ISBN: 9781259911149
Author: BAUER, Richard C., Birk, James P., Marks, Pamela
Publisher: Mcgraw-hill Education,
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Chapter 6, Problem 48QP
Interpretation Introduction

Interpretation:

The molecules to be reacted and the final composition of the mixture in the given reaction are to be identified.

Concept Introduction:

A chemical equation is balanced when the number of atoms of each element and the charges on the atoms for both the reactants and products are the same.

Expert Solution & Answer
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Explanation of Solution

Given Information: A reaction is given in the question.

Initially, 0.130 g of C4H10 is mixed. So, the mass of oxygen that would be reacted can be calculated as follows.

Mass of O2=0.130 g  C4H10 ×mol C4H1058.12 g of C4H10×13 mol O22 mol C2H6×32.00 g O2mol O2 =0.465 g O2

0.580 g O2 is initially present in the reaction, but the reaction consumes only 0.465 g O2 . Thus, C4H10 is a limiting reactant. The final composition of the mass of CO2 is calculated with the help of the limiting reactant, C4H10 , which is as follows.

Mass of CO2=0.130 g  C4H10 ×mol C4H1058.12 g of C4H10×mol CO22 mol C2H6×44.01 g CO2mol CO2 =0.394 g O2

The final composition of the mass of H2O is calculated with the help of the limiting reactant, C4H10 , which is as follows.

Mass of H2O=0.130 g  C4H10 ×mol C4H1058.12 g of C4H10×10 mol H2O2 mol C4H6×18.02 g H2Omol H2O =0.202 g H2O

The number of molecules of butane and oxygen that react to form the desirable amount of carbon dioxide and water is as follows:

2C4H10g+13O2g8CO2g+10H2OgC2H67O2CO2H2OIntially mixed0.130 g0.580 g0.00 g0.00 gHow much react0.130 g0.465 gComposition of final mixture0.000 g0.115 g0.394 g0.202 g

Conclusion

The molecules to be reacted and the final composition of the mixture in the given reaction are shown in the table above.

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Chapter 6 Solutions

Introduction To Chemistry

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