Laboratory Experiments in Microbiology (11th Edition)
11th Edition
ISBN: 9780321994936
Author: Ted R. Johnson, Christine L. Case
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 6, Problem 3CT
Summary Introduction
To write:
Acidic congo red does not have the suspended particles unlike the nigrosin butprovides the presence of a negative stain. Give the basis for this stain.
Introduction:
Heat fixing:
After the drying of smear at the room temperature on the slide. This slide is gripped with the help of tongs or a clothespin. Then it is passed across the flame of a Bunsen burner and numerous times to heat-kill. It attaches the organism to the slide. Heat fixation usually conserves generally the morphology but not an internal structure.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Outline the negative feedback loop that allows us to maintain a healthy water concentration in our blood.
You may use diagram if you wish
Give examples of fat soluble and non-fat soluble hormones
Just click view full document and register so you can see the whole document. how do i access this. following from the previous question; https://www.bartleby.com/questions-and-answers/hi-hi-with-this-unit-assessment-psy4406-tp4-report-assessment-material-case-stydu-ms-alecia-moore.-o/5e09906a-5101-4297-a8f7-49449b0bb5a7.
on Google this image comes up and i have signed/ payed for the service and unable to access the full document. are you able to copy and past to this response. please see the screenshot from google page. unfortunality its not allowing me attch the image
can you please show me the mathmetic calculation/ workout for the reult section
Chapter 6 Solutions
Laboratory Experiments in Microbiology (11th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Skryf n kortkuns van die Egyptians pyramids vertel ñ story. Maximum 500 woordearrow_forward1.)What cross will result in half homozygous dominant offspring and half heterozygous offspring? 2.) What cross will result in all heterozygous offspring?arrow_forward1.Steroids like testosterone and estrogen are nonpolar and large (~18 carbons). Steroids diffuse through membranes without transporters. Compare and contrast the remaining substances and circle the three substances that can diffuse through a membrane the fastest, without a transporter. Put a square around the other substance that can also diffuse through a membrane (1000x slower but also without a transporter). Molecule Steroid H+ CO₂ Glucose (C6H12O6) H₂O Na+ N₂ Size (Small/Big) Big Nonpolar/Polar/ Nonpolar lonizedarrow_forward
- what are the answer from the bookarrow_forwardwhat is lung cancer why plants removes liquid water intead water vapoursarrow_forward*Example 2: Tracing the path of an autosomal dominant trait Trait: Neurofibromatosis Forms of the trait: The dominant form is neurofibromatosis, caused by the production of an abnormal form of the protein neurofibromin. Affected individuals show spots of abnormal skin pigmentation and non-cancerous tumors that can interfere with the nervous system and cause blindness. Some tumors can convert to a cancerous form. i The recessive form is a normal protein - in other words, no neurofibromatosis.moovi A typical pedigree for a family that carries neurofibromatosis is shown below. Note that carriers are not indicated with half-colored shapes in this chart. Use the letter "N" to indicate the dominant neurofibromatosis allele, and the letter "n" for the normal allele. Nn nn nn 2 nn Nn A 3 N-arrow_forward
- I want to be a super nutrition guy what u guys like recommend mearrow_forwardPlease finish the chart at the bottom. Some of the answers have been filled in.arrow_forward9. Aerobic respiration of one lipid molecule. The lipid is composed of one glycerol molecule connected to two fatty acid tails. One fatty acid is 12 carbons long and the other fatty acid is 18 carbons long in the figure below. Use the information below to determine how much ATP will be produced from the glycerol part of the lipid. Then, in part B, determine how much ATP is produced from the 2 fatty acids of the lipid. Finally put the NADH and ATP yields together from the glycerol and fatty acids (part A and B) to determine your total number of ATP produced per lipid. Assume no other carbon source is available. 18 carbons fatty acids 12 carbons 9 glycerol A. Glycerol is broken down to glyceraldehyde 3-phosphate, a glycolysis intermediate via the following pathway shown in the figure below. Notice this process costs one ATP but generates one FADH2. Continue generating ATP with glyceraldehyde-3-phosphate using the standard pathway and aerobic respiration. glycerol glycerol-3- phosphate…arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles Of Radiographic Imaging: An Art And A ...Health & NutritionISBN:9781337711067Author:Richard R. Carlton, Arlene M. Adler, Vesna BalacPublisher:Cengage Learning- Surgical Tech For Surgical Tech Pos CareHealth & NutritionISBN:9781337648868Author:AssociationPublisher:Cengage
Principles Of Radiographic Imaging: An Art And A ...
Health & Nutrition
ISBN:9781337711067
Author:Richard R. Carlton, Arlene M. Adler, Vesna Balac
Publisher:Cengage Learning
Surgical Tech For Surgical Tech Pos Care
Health & Nutrition
ISBN:9781337648868
Author:Association
Publisher:Cengage