INQUIRY INTO PHYSICS-EBOOK
INQUIRY INTO PHYSICS-EBOOK
8th Edition
ISBN: 9780357540039
Author: Ostdiek
Publisher: CENGAGE L
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Chapter 6, Problem 38Q
To determine

The energy of the waves from highest to lowest.

Expert Solution & Answer
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Answer to Problem 38Q

The energy of the waves will be arranged as:

10×1026>6.63×1026>3.3×1026II=VI>I=V>III=IV.

Explanation of Solution

Given data:

Wave I: λ = 3m.

Wave II: λ = 2m.

Wave III: λ = 6m.

Wave IV: λ = 6m.

Wave V: λ = 3m.

Wave VI: λ = 2m.

Formula used:

The energy of the waves are calculated by the following formula:

E=hνc=λν.

Calculation:

Having the known values, the energy of the wave is calculated as:

E=hνc=λν

Where, E is the energy of the wave.

h is the Planck’s constant; h=6.63×1034Js

c is the velocity of light; c=3×108ms1

Wave I:λ=3mν=cλ=3× 1083=108s1E=hνE=(6.63×1034)( 108)=6.63×1026Js1Wave II:λ=2mν=cλ=3× 1082=15×107s1E=hνE=(6.63×1034)(15× 107)=10×1026Js1Wave III:λ=6mν=cλ=3× 1086=0.5×108s1E=hνE=(6.63×1034)(0.5× 108)=3.3×1026Js1Wave IV:λ=6mν=cλ=3× 1086=0.5×108s1E=hνE=(6.63×1034)(0.5× 108)=3.3×1026Js1

Wave V:λ=3mν=cλ=3× 1083=108s1E=hνE=(6.63×1034)( 108)=6.63×1026Js1

Wave VI:λ=2mν=cλ=3× 1082=15×107s1E=hνE=(6.63×1034)(15× 107)=10×1026Js1.

Conclusion:

Thus, the energy of the waves are arranged as:

10×1026>6.63×1026>3.3×1026II=VI>I=V>III=IV.

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Chapter 6 Solutions

INQUIRY INTO PHYSICS-EBOOK

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