Continuation of Problem 8. Now assume that Eq. 6-14 gives the magnitude of the air drag force on the typical 20 kg stone, which presents to the wind a vertical cross-sectional area of 0.040 m 2 and has a drag coefficient C of 0.80. Take the air density to be 1.21 kg/m 3 , and the coefficient of kinetic friction to be 0.80. (a) In kilometers per hour, what wind speed V along the ground is needed to maintain the stone’s motion once it has started moving? Because winds along the ground are retarded by the ground, the wind speeds reported for storms are often measured at a height of 10 m. Assume wind speeds are 2.00 times those along the ground. (b) For your answer to (a), what wind speed would be reported for the storm? (c) Is that value reasonable for a high-speed wind in a storm? (Story continues with Problem 65.)
Continuation of Problem 8. Now assume that Eq. 6-14 gives the magnitude of the air drag force on the typical 20 kg stone, which presents to the wind a vertical cross-sectional area of 0.040 m 2 and has a drag coefficient C of 0.80. Take the air density to be 1.21 kg/m 3 , and the coefficient of kinetic friction to be 0.80. (a) In kilometers per hour, what wind speed V along the ground is needed to maintain the stone’s motion once it has started moving? Because winds along the ground are retarded by the ground, the wind speeds reported for storms are often measured at a height of 10 m. Assume wind speeds are 2.00 times those along the ground. (b) For your answer to (a), what wind speed would be reported for the storm? (c) Is that value reasonable for a high-speed wind in a storm? (Story continues with Problem 65.)
Continuation of Problem 8. Now assume that Eq. 6-14 gives the magnitude of the air drag force on the typical 20 kg stone, which presents to the wind a vertical cross-sectional area of 0.040 m2 and has a drag coefficient C of 0.80. Take the air density to be 1.21 kg/m3, and the coefficient of kinetic friction to be 0.80. (a) In kilometers per hour, what wind speed V along the ground is needed to maintain the stone’s motion once it has started moving? Because winds along the ground are retarded by the ground, the wind speeds reported for storms are often measured at a height of 10 m. Assume wind speeds are 2.00 times those along the ground. (b) For your answer to (a), what wind speed would be reported for the storm? (c) Is that value reasonable for a high-speed wind in a storm? (Story continues with Problem 65.)
Is work function of a metals surface related to surface energy and surface tension? What is the need to the work function component in the math of tension of metal surfaces that cannot be provided by existing equations of surface energy and surface tension? What are the key differences in each parameter and variables that allow for a differentiation of each function? What has a more significant meaning work function, surface tension or surface energy? Are there real differences and meaning? Please clarify and if possible provide examples . Does surface tension dependant on thickness of a metal or type of metal surface all having the same thickness? Clearly temperature has a profound change on surface tension what other variables besides temperature are key to surface tension. What if any is there a connection between crystal structure of the element and surface energy and tension? This is NOT a Assignment Question!!!
The cylindrical beam of a 12.7-mW laser is 0.920 cm in diameter. What is the rms value of the electric field?
V/m
Consider a rubber rod that has been rubbed with fur to give the rod a net negative charge, and a glass rod that has been rubbed with silk to give it a net positive charge. After being charged by contact by the fur and silk...?
a. Both rods have less mass
b. the rubber rod has more mass and the glass rod has less mass
c. both rods have more mass
d. the masses of both rods are unchanged
e. the rubber rod has less mass and the glass rod has mroe mass
Human Physiology: An Integrated Approach (8th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.