ELEMENTARY STATISTICS W/CONNECT >C<
ELEMENTARY STATISTICS W/CONNECT >C<
3rd Edition
ISBN: 9781307235012
Author: Navidi
Publisher: MCG/CREATE
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Chapter 6, Problem 2RE

a.

To determine

To find the mean of the given probability distribution.

a.

Expert Solution
Check Mark

Answer to Problem 2RE

Mean = 8.37

Explanation of Solution

Given:

    x P ( x )
    60.21
    70.12
    80.29
    90.11
    100.01
    110.26

Concept used:

  Mean=x.P(x)

    x P ( x )x.P(x)
    60.211.26
    70.120.84
    80.292.32
    90.110.99
    100.010.1
    110.262.86
    Sum18.37

Since the x.P(x) = 8.37, from the above table.

Therefore, the mean of the given distribution is 8.37.

b.

To determine

To find the Variance of the given probability distribution.

b.

Expert Solution
Check Mark

Answer to Problem 2RE

Variance = 3.3131

Explanation of Solution

Given:

    x P ( x )
    60.21
    70.12
    80.29
    90.11
    100.01
    110.26

Concept used:

  Variance=x2.P(x)[x.P(x)]2

    x P ( x )x.P(x)x2.P(x)
    60.211.267.56
    70.120.845.88
    80.292.3218.56
    90.110.998.91
    100.010.11
    110.262.8631.46
    Sum18.3773.37

From the above table:

  x.P(x)=8.37x2.P(x)=73.37

Therefore, the variance is,

  Variance=x2.P(x)[x.P(x)]2=73.37(8.37)2=3.3131

c.

To determine

To find the Standard Deviation of the given probability distribution.

c.

Expert Solution
Check Mark

Answer to Problem 2RE

Standard Deviation = 1.82

Explanation of Solution

Given:

    x P ( x )
    60.21
    70.12
    80.29
    90.11
    100.01
    110.26

Concept used:

  Standard Deviation =x2.P(x)[x.P( x)]2

    x P ( x )x.P(x)x2.P(x)
    60.211.267.56
    70.120.845.88
    80.292.3218.56
    90.110.998.91
    100.010.11
    110.262.8631.46
    Sum18.3773.37

From the above table:

  x.P(x)=8.37x2.P(x)=73.37

Therefore, the variance is,

  Standard Deviation=x2.P(x) [ x.P( x )]2=73.37 ( 8.37 )2=3.3131=1.82

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Chapter 6 Solutions

ELEMENTARY STATISTICS W/CONNECT >C<

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