Chapter 6, Problem 2CLT

To determine

Converted angle in degrees. Round the answer to one decimalplace.

Answer to Problem 2CLT

Angle in degrees is ${83.1}^0$

Explanation of Solution

Given info:

  $\theta =-1.45$

Formula used:

  $\begin{array}{l}\text{Angle in radian = Angle in degree }\times \frac{\pi }{180}\\ \text{Angle in degree = Angle in radian}\times \frac{180}{\pi }\end{array}$

Calculation:

We have

  $\begin{array}{l}\text{Angle in degree = Angle in radian}\times \frac{180}{\pi }\\ \text{Angle in degree = }-1.45\times \frac{180}{\pi }={83.1}^0\end{array}$

Angle in degrees is ${83.1}^0$

Conclusion:

Thus,theangle in degrees is ${83.1}^0$