EBK INTRODUCTION TO CHEMISTRY
EBK INTRODUCTION TO CHEMISTRY
5th Edition
ISBN: 9781260162165
Author: BAUER
Publisher: MCGRAW HILL BOOK COMPANY
Question
Book Icon
Chapter 6, Problem 26QP

(a)

Interpretation Introduction

Interpretation:

The given equation C6H12l+O2gCO2g+H2Og is to be balanced and after that, the number of grams of the first reactant that is required to react completely to give 1.70 g of the product indicated in the boldface is to be determined.

(a)

Expert Solution
Check Mark

Explanation of Solution

The relation among the number of moles, molar mass and mass is,

n= mMM

Here, n is the number of moles, m is mass and MM is molar mass.

By rearranging the above equation mass can be determined as follows:

m=n×MM …..(1)

The balanced equation is,

C6H12l+9O2g6CO2g+6H2Og

The molar mass of CO2 is 44.01g/mol and C6H12 is 84.16g/mol . The mass of C6H12 is determined by using equation (1) as follows:

m=1.70g CO2×mol CO244.01g CO2×1 mol C6H126mol CO2×84.16g C6H121mol C6H12=0.542 g C6H12

(b)

Interpretation Introduction

Interpretation:

The given equation NI3sN2g+I2s is to be balanced and after that, the number of grams of the first reactant that is required to react completely to give 1.70 g of the product indicated in the boldface is to be determined.

(b)

Expert Solution
Check Mark

Explanation of Solution

The balanced equation is,

2NI3sN2g+3I2s

The molar mass of I2 is 253.8g/mol and NI3 is 394.7g/mol . The mass of NI3 is determined by using equation (1) as follows:

m=1.70g I2×mol I2253.8g I2×2 mol NI33mol I2×394.7g NI31mol NI3=1.76 g NI3

(c)

Interpretation Introduction

Interpretation:

The given equation Nas+O2gN2Os is to be balanced and after that, the number of grams of the first reactant that is required to react completely to give 1.70 g of the product indicated in the boldface is to be determined.

(c)

Expert Solution
Check Mark

Explanation of Solution

The balanced equation is,

4Nas+O2g2Na2Os

The molar mass of Na2O is 61.98g/mol and Na is 22.99g/mol . The mass of Na is determined by using equation (1) as follows:

m=1.70g Na2O×mol Na2O61.98g Na2O×4 mol Na2mol Na2O×22.99g Na1mol Na=1.26 g Na

(d)

Interpretation Introduction

Interpretation:

The given equation Cas+HClaqCaCl2aq+H2g is to be balanced and after that, the number of grams of the first reactant that is required to react completely to give 1.70 g of the product indicated in the boldface is to be determined.

(d)

Expert Solution
Check Mark

Explanation of Solution

The balanced equation is,

Cas+2HClaqCaCl2aq+H2g

The molar mass of H2 is 2.016g/mol and Ca is 40.08g/mol . The mass of Ca is determined by using equation (1) as follows:

m=1.70g H2×mol H22.016g H2×1 mol Ca1mol H2×40.08g Ca1mol Ca=33.8 g Ca

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Classification of boranes.
What is the pH of a solution made by adding 10-2 M sodium benzoate (C6H5COONa) to pure water, taking into account nonideal solute behavior? Benzoate is the conjugate base of benzoic acid (Ka = 6.25×10-5), a common preservative added to food and beverages.
Show work. don't give Ai generated solution

Chapter 6 Solutions

EBK INTRODUCTION TO CHEMISTRY

Ch. 6 - Prob. 4PPCh. 6 - Consider the combination reaction of nitrogen gas...Ch. 6 - Prob. 6PPCh. 6 - Prob. 7PPCh. 6 - Prob. 8PPCh. 6 - Prob. 9PPCh. 6 - Prob. 10PPCh. 6 - Prob. 11PPCh. 6 - Prob. 12PPCh. 6 - Prob. 13PPCh. 6 - Prob. 14PPCh. 6 - Prob. 1QPCh. 6 - Prob. 2QPCh. 6 - Prob. 3QPCh. 6 - Prob. 4QPCh. 6 - Prob. 5QPCh. 6 - Prob. 6QPCh. 6 - Prob. 7QPCh. 6 - Prob. 8QPCh. 6 - Prob. 9QPCh. 6 - Prob. 10QPCh. 6 - Prob. 11QPCh. 6 - Prob. 12QPCh. 6 - Prob. 13QPCh. 6 - Prob. 14QPCh. 6 - Prob. 15QPCh. 6 - Prob. 16QPCh. 6 - Prob. 17QPCh. 6 - Prob. 18QPCh. 6 - Prob. 19QPCh. 6 - Prob. 20QPCh. 6 - Prob. 21QPCh. 6 - Prob. 22QPCh. 6 - Prob. 23QPCh. 6 - Prob. 24QPCh. 6 - Prob. 25QPCh. 6 - Prob. 26QPCh. 6 - Prob. 27QPCh. 6 - Prob. 28QPCh. 6 - Prob. 29QPCh. 6 - Prob. 30QPCh. 6 - Prob. 31QPCh. 6 - Prob. 32QPCh. 6 - Prob. 33QPCh. 6 - The balanced equation for the reaction of chromium...Ch. 6 - Prob. 35QPCh. 6 - Prob. 36QPCh. 6 - Prob. 37QPCh. 6 - Prob. 38QPCh. 6 - Prob. 39QPCh. 6 - Prob. 40QPCh. 6 - Prob. 41QPCh. 6 - Prob. 42QPCh. 6 - Prob. 43QPCh. 6 - Prob. 44QPCh. 6 - Prob. 45QPCh. 6 - Prob. 46QPCh. 6 - Prob. 47QPCh. 6 - Prob. 48QPCh. 6 - Prob. 49QPCh. 6 - Prob. 50QPCh. 6 - Prob. 51QPCh. 6 - Prob. 52QPCh. 6 - Prob. 53QPCh. 6 - Prob. 54QPCh. 6 - Prob. 55QPCh. 6 - A student added zinc metal to copper(II) nitrate...Ch. 6 - Prob. 57QPCh. 6 - Prob. 58QPCh. 6 - When I2 is mixed with excess H2, 0.80 mol HI is...Ch. 6 - The reaction of lithium metal and water to form...Ch. 6 - Prob. 61QPCh. 6 - Prob. 62QPCh. 6 - If energy cannot be created or destroyed, what...Ch. 6 - Prob. 64QPCh. 6 - Prob. 65QPCh. 6 - Prob. 66QPCh. 6 - Prob. 67QPCh. 6 - Prob. 68QPCh. 6 - Prob. 69QPCh. 6 - Prob. 70QPCh. 6 - Prob. 71QPCh. 6 - Prob. 72QPCh. 6 - Prob. 73QPCh. 6 - Prob. 74QPCh. 6 - Prob. 75QPCh. 6 - Prob. 76QPCh. 6 - Prob. 77QPCh. 6 - Prob. 78QPCh. 6 - Prob. 79QPCh. 6 - Prob. 80QPCh. 6 - Prob. 81QPCh. 6 - Prob. 82QPCh. 6 - Prob. 83QPCh. 6 - Prob. 84QPCh. 6 - Prob. 85QPCh. 6 - Prob. 86QPCh. 6 - Prob. 87QPCh. 6 - Prob. 88QPCh. 6 - Prob. 89QPCh. 6 - Prob. 90QPCh. 6 - Prob. 91QPCh. 6 - Prob. 92QPCh. 6 - Prob. 93QPCh. 6 - Prob. 94QPCh. 6 - Prob. 95QPCh. 6 - Prob. 96QPCh. 6 - Prob. 97QPCh. 6 - Prob. 98QPCh. 6 - Prob. 99QPCh. 6 - Prob. 100QPCh. 6 - Prob. 101QPCh. 6 - Prob. 102QPCh. 6 - Prob. 103QPCh. 6 - Prob. 104QPCh. 6 - Prob. 105QPCh. 6 - Prob. 106QPCh. 6 - Prob. 107QPCh. 6 - Prob. 108QPCh. 6 - Prob. 109QPCh. 6 - Prob. 110QPCh. 6 - The balanced equation for the combustion of octane...Ch. 6 - Prob. 112QPCh. 6 - Prob. 113QPCh. 6 - Prob. 114QPCh. 6 - Prob. 115QPCh. 6 - Prob. 116QPCh. 6 - Prob. 117QPCh. 6 - Prob. 118QPCh. 6 - Prob. 119QPCh. 6 - Prob. 120QPCh. 6 - Prob. 121QPCh. 6 - Prob. 122QPCh. 6 - Prob. 123QPCh. 6 - Prob. 124QPCh. 6 - Prob. 125QPCh. 6 - A 150.0-g sample of copper is heated to 89.3C. The...Ch. 6 - How many moles of aqueous magnesium ions and...Ch. 6 - Prob. 128QPCh. 6 - How many moles of aqueous potassium ions and...Ch. 6 - Prob. 130QPCh. 6 - Prob. 131QPCh. 6 - Prob. 132QPCh. 6 - Prob. 133QPCh. 6 - Prob. 134QPCh. 6 - Prob. 135QPCh. 6 - Prob. 136QPCh. 6 - Prob. 137QPCh. 6 - Prob. 138QPCh. 6 - Prob. 139QPCh. 6 - Prob. 140QPCh. 6 - Prob. 141QPCh. 6 - When calculating percent yield for a reaction, the...Ch. 6 - Prob. 143QPCh. 6 - Prob. 144QPCh. 6 - Prob. 145QPCh. 6 - Prob. 146QP
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Text book image
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781285199030
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning