(a)
Interpretation:
The chemical formula of sodium chromate has to be written.
(a)
Answer to Problem 22PE
The chemical formula of sodium chromate is
Explanation of Solution
In sodium chromate, the cation is sodium
The chemical formula of sodium chromate is
(b)
Interpretation:
The chemical formula of magnesium hydride has to be written.
(b)
Answer to Problem 22PE
The chemical formula of magnesium hydride is
Explanation of Solution
In magnesium hydride, the cation is magnesium
The chemical formula of magnesium hydride is
(c)
Interpretation:
The chemical formula of nickel (II) acetate has to be written.
(c)
Answer to Problem 22PE
The chemical formula of nickel (II) acetate is
Explanation of Solution
In nickel (II) acetate, the cation is nickel (II)
The chemical formula of nickel (II) acetate is
(d)
Interpretation:
The chemical formula of calcium chlorate has to be written.
(d)
Answer to Problem 22PE
The chemical formula of calcium chlorate is
Explanation of Solution
In calcium chlorate, the cation is calcium
The chemical formula of calcium chlorate is
(e)
Interpretation:
The chemical formula of magnesium bromate has to be written.
(e)
Answer to Problem 22PE
The chemical formula of magnesium bromate is
Explanation of Solution
In magnesium bromate, the cation is magnesium
The chemical formula of magnesium bromate is
(f)
Interpretation:
The chemical formula of potassium dihydrogen phosphate has to be written.
(f)
Answer to Problem 22PE
The chemical formula of potassium dihydrogen phosphate is
Explanation of Solution
In potassium dihydrogen phosphate, the cation is potassium
The chemical formula of potassium dihydrogen phosphate is
(g)
Interpretation:
The chemical formula of manganese (II) hydroxide has to be written.
(g)
Answer to Problem 22PE
The chemical formula of manganese (II) hydroxide is
Explanation of Solution
In manganese (II) hydroxide, the cation is manganese (II)
The chemical formula of manganese (II) hydroxide is
(h)
Interpretation:
The chemical formula of cobalt (II) hydrogen carbonate has to be written.
(h)
Answer to Problem 22PE
The chemical formula of cobalt (II) hydrogen carbonate is
Explanation of Solution
In cobalt (II) hydrogen carbonate, the cation is cobalt (II)
The chemical formula of cobalt (II) hydrogen carbonate is
(i)
Interpretation:
The chemical formula of sodium hypochlorite has to be written.
(i)
Answer to Problem 22PE
The chemical formula of sodium hypochlorite is
Explanation of Solution
In sodium hypochlorite, the cation is sodium
The chemical formula of sodium hypochlorite is
(j)
Interpretation:
The chemical formula of barium perchlorate has to be written.
(j)
Answer to Problem 22PE
The chemical formula of barium perchlorate is
Explanation of Solution
In barium perchlorate, the cation is barium
The chemical formula of barium perchlorate is
(k)
Interpretation:
The chemical formula of chromium (III) sulfite has to be written.
(k)
Answer to Problem 22PE
The chemical formula of chromium (III) sulfite is
Explanation of Solution
In chromium (III) sulfite, the cation is chromium (III)
The chemical formula of chromium (III) sulfite is
(l)
Interpretation:
The chemical formula of antimony (III) sulfate has to be written.
(l)
Answer to Problem 22PE
The chemical formula of antimony (III) sulfate is
Explanation of Solution
In antimony (III) sulfate, the cation is antimony (III)
The chemical formula of antimony (III) sulfate is
(m)
Interpretation:
The chemical formula of sodium oxalate has to be written.
(m)
Answer to Problem 22PE
The chemical formula of sodium oxalate is
Explanation of Solution
In sodium oxalate, the cation is sodium
The chemical formula of sodium oxalate is
(n)
Interpretation:
The chemical formula of potassium thiocyanate has to be written.
(n)
Answer to Problem 22PE
The chemical formula of potassium thiocyanate is
Explanation of Solution
In potassium thiocyanate, the cation is potassium
The chemical formula of potassium thiocyanate is
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Chapter 6 Solutions
Foundations of College Chemistry, Binder Ready Version
- Nonearrow_forwardDraw the structure of the product of the reaction given the IR and MS data. Spectral analysis of the product reveals: MS: M 150, M-15, M-43 CH.COCI AICI, IR: 3150-3000 cm, 2950-2850 cm and 1700 cmarrow_forwardPart II. Identify whether the two protons in blue are homotopic, enantiopic, diasteriotopic, or heterotopic. a) HO b) Bri H HH c) d) H H H Br 0arrow_forward
- Nonearrow_forwardChoose the option that is decreasing from biggest to smallest. Group of answer choices: 100 m, 10000 mm, 100 cm, 100000 um, 10000000 nm 10000000 nm, 100000 um, 100 cm, 10000 mm, 100 m 10000000 nm, 100000 um, 10000 mm, 100 cm, 100 m 100 m, 100 cm, 10000 mm, 100000 um, 10000000 nmarrow_forwardQ1. (a) Draw equations for homolytic and heterolytic cleavages of the N-H bond in NH3. Use curved arrows to show the electron movement. (b) Draw equations for homolytic and heterolytic cleavages of the N-H bond in NH4*. Use curved arrows to show the electron movement.arrow_forward
- Part II. count the expected number of signals in the 1H-NMR spectrum of these compounds HO 0 одев * Cl -cl "D"arrow_forwardPart I. Create a splitting tree diagram to predict the multiplet pattern of proton Hb in the compound below: 3 (Assume that "Jab >>> ³JbC) Ha Hb He он Ha NH2 Ha HCarrow_forwardNonearrow_forward
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning