EBK MATLAB: AN INTRODUCTION WITH APPLIC
EBK MATLAB: AN INTRODUCTION WITH APPLIC
5th Edition
ISBN: 8220102007642
Author: GILAT
Publisher: YUZU
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Chapter 6, Problem 1P
To determine

(a) To evaluate:

The expression 124<5×3 without using MATLAB, then check the answer with MATLAB.

Expert Solution
Check Mark

Answer to Problem 1P

Solution:

The value of the expression 124<5×3 is 1.

Explanation of Solution

The given expression is,

124<5×3

Assign 1 if the comparison is correct otherwise assign 0.

Simplify the above equation,

124<5×38<151

Write the MATLAB script to evaluate the expression 124<5×3.

MATLAB Code:

%Evaluate the expression

12-4<5.*3

%Assign 1 if the comparison is correct otherwise assign 0.

Save the MATLAB script with name, Chapter6_29864_6_1Pa.m in the current folder. Execute the script by typing the script name at the command window to evaluate the expression 6×4>323.

Result:

EBK MATLAB: AN INTRODUCTION WITH APPLIC, Chapter 6, Problem 1P , additional homework tip  1

To determine

(b) To evaluate:

The expression y=8/4>6×342>3 without using MATLAB, then check the answer with MATLAB.

Expert Solution
Check Mark

Answer to Problem 1P

Solution:

The value of the expression y=8/4>6×342>3 is 1.

Explanation of Solution

The given expression is,

y=8/4>6×342>3

Assign 1 if the comparison is correct otherwise assign 0.

Simplify the above equation,

y=8/4>6×342>3(2>2)>30>11

Write the MATLAB script to evaluate the expression y=8/4>6×342>3.

MATLAB Code:

%Evaluate the expression

y = 8/4>6*3-4^2>-3

%Assign 1 if the comparison is correct otherwise assign 0.

Save the MATLAB script with name, Chapter6_29864_6_1Pb.m in the current folder. Execute the script by typing the script name at the command window to evaluate the expression y=8/4>6×342>3.

Result:

EBK MATLAB: AN INTRODUCTION WITH APPLIC, Chapter 6, Problem 1P , additional homework tip  2

To determine

(c) To evaluate:

The expression y=3<(812)+2×(5>18/64)2 without using MATLAB, then check the answer with MATLAB.

Expert Solution
Check Mark

Answer to Problem 1P

Solution:

The value of the expression y=3<(812)+2×(5>18/64)2 is 1.

Explanation of Solution

The given expression is,

y=3<(812)+2×(5>18/64)2

Assign 1 if the comparison is correct otherwise assign 0.

Simplify the above equation,

y=3<(812)+2×(5>18/64)23<(4)+2×(25>1)3<(4)+21

Write the MATLAB script to evaluate the expression y=3<(812)+2×(5>18/64)2.

MATLAB Code:

%Evaluate the expression

y=-3<(8-12)+2*(5>18/6-4)^2

%Assign 1 if the comparison is correct otherwise assign 0.

Save the MATLAB script with name, Chapter6_29864_6_1Pc.m in the current folder. Execute the script by typing the script name at the command window to evaluate the expression y=3<(812)+2×(5>18/64)2.

Result:

EBK MATLAB: AN INTRODUCTION WITH APPLIC, Chapter 6, Problem 1P , additional homework tip  3

To determine

(d) To evaluate:

The expression (5+0)×6==3+3×0 without using MATLAB, then check the answer with MATLAB.

Expert Solution
Check Mark

Answer to Problem 1P

Solution:

The value of the expression (5+0)×6==3+3×0 is 1.

Explanation of Solution

The given expression is,

(5+0)×6==3+3×0

The sign ~ represents NOT operation. Assign 0 if NOT operation contains non-zero term otherwise assign 1.

Assign 1 if the comparison is correct otherwise assign 0.

Simplify the above equation,

(5+0)×6==3+3×06==61

Write the MATLAB script to evaluate the expression (5+0)×6==3+3×0.

MATLAB Code:

%Evaluate the expression

(~5+~0)*6==3+3*~0

%Assign 1 if the comparison is correct otherwise assign 0.

Save the MATLAB script with name, Chapter6_29864_6_1Pd.m in the current folder. Execute the script by typing the script name at the command window to evaluate the expression (5+0)×6==3+3×0.

Result:

EBK MATLAB: AN INTRODUCTION WITH APPLIC, Chapter 6, Problem 1P , additional homework tip  4

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c) An RC circuit is given in Figure Q1.1, where Vi(t) and Vo(t) are the input and output voltages. (i) Derive the transfer function of the circuit. (ii) With a unit step change of Vi(t) applied to the circuit, derive the time response of Vo(t) with this step change. Vi(t) C₁ Vo(1) R₂ C2 C3 | R = 20 ΚΩ = 50 ΚΩ C=C2=C3=25 μF Figure Q1.1. RC circuit.
c) An RC circuit is given in Figure Q1. vi(t) and vo (t) are the input and output voltages. (i) Derive the transfer function of the circuit. (ii) With a unit step change vi(t) applied to the circuit, derive and sketch the time response of the circuit. R₁ R2 v₁(t) R3 C₁ v₁(t) R₁ = R₂ = 10 k R3 = 100 kn C₁ = 100 μF Figure Q1. RC circuit.

Chapter 6 Solutions

EBK MATLAB: AN INTRODUCTION WITH APPLIC

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