Chapter 6, Problem 1P

An uncharged $\text{100-μF}$ capacitor is charged by a constant currant of 1 mA. Find the voltage across the capacitor after 4 s.

To determine

The voltage across the capacitor after 4 seconds.

Answer to Problem 1P

  $v=40\text{V}$

Explanation of Solution

Given:

  $\begin{array}{l}C=100\text{μF}\\ I=1\text{mA}\end{array}$

Calculation:

The figure can be drawn as:

The voltage across the capacitor after 4 seconds will be:

  $\begin{array}{l}v=\frac{it}{c}\\ v=\frac{1\times 4\left({10}^{-3}\right)}{100\times {10}^{-6}}\\ v=40\text{V}\end{array}$