
Explain why a balloon that has been rubbed might stick to a wall for a while.

The reason for the balloon to stick to a wall after it has been rubbed.
Answer to Problem 1CQ
Rubbing the balloon transfers electrons to the balloon making the balloon negatively charged. When this balloon is brought near a wall, the negative charge on the balloon repels the electrons on the surface of the wall giving a small surface on the wall near the balloon a positive charge. These unlike charges attract causing the balloon to stick to the wall.
Explanation of Solution
Electrons can move from one object to the other by friction. Electrons being negatively charged, the object that receives an excess of electrons becomes a negatively charged object. As the electric charge is confined to an object and is at rest, it is called an electrostatic charge or static electricity.
On rubbing the balloon with an object, because of friction, electrons are transferred to the balloon making the balloon negatively charged. The negative charge on the balloon from an excess of electrons is momentarily at rest making it an electrostatic charge. When this balloon is brought near a wall, the negative charge on the balloon repels the electrons on the surface of the wall giving a small surface on the wall near the balloon a positive charge. These unlike charges attract causing the balloon to stick to the wall.
Conclusion:
When the charged balloon is brought near a wall, the negative charge on the balloon repels the electrons on the surface of the wall giving a small surface on the wall near the balloon a positive charge. These unlike charges attract causing the balloon to stick to the wall.
Want to see more full solutions like this?
Chapter 6 Solutions
Integrated Science
Additional Science Textbook Solutions
Applications and Investigations in Earth Science (9th Edition)
Cosmic Perspective Fundamentals
Campbell Biology: Concepts & Connections (9th Edition)
Essentials of Human Anatomy & Physiology (12th Edition)
Introductory Chemistry (6th Edition)
Campbell Biology (11th Edition)
- please help me solve this questions. show all calculations and a good graph too :)arrow_forwardWhat is the force (in N) on the 2.0 μC charge placed at the center of the square shown below? (Express your answer in vector form.) 5.0 με 4.0 με 2.0 με + 1.0 m 1.0 m -40 με 2.0 μCarrow_forwardWhat is the force (in N) on the 5.4 µC charge shown below? (Express your answer in vector form.) −3.1 µC5.4 µC9.2 µC6.4 µCarrow_forward
- An ideal gas in a sealed container starts out at a pressure of 8900 N/m2 and a volume of 5.7 m3. If the gas expands to a volume of 6.3 m3 while the pressure is held constant (still at 8900 N/m2), how much work is done by the gas? Give your answer as the number of Joules.arrow_forwardThe outside temperature is 25 °C. A heat engine operates in the environment (Tc = 25 °C) at 50% efficiency. How hot does it need to get the high temperature up to in Celsius?arrow_forwardGas is compressed in a cylinder creating 31 Joules of work on the gas during the isothermal process. How much heat flows from the gas into the cylinder in Joules?arrow_forward
- The heat engine gives 1100 Joules of energy of high temperature from the burning gasoline by exhausting 750 Joules to low-temperature . What is the efficiency of this heat engine in a percentage?arrow_forwardL₁ D₁ L₂ D2 Aluminum has a resistivity of p = 2.65 × 10 8 2. m. An aluminum wire is L = 2.00 m long and has a circular cross section that is not constant. The diameter of the wire is D₁ = 0.17 mm for a length of L₁ = 0.500 m and a diameter of D2 = 0.24 mm for the rest of the length. a) What is the resistance of this wire? R = Hint A potential difference of AV = 1.40 V is applied across the wire. b) What is the magnitude of the current density in the thin part of the wire? Hint J1 = c) What is the magnitude of the current density in the thick part of the wire? J₂ = d) What is the magnitude of the electric field in the thin part of the wire? E1 = Hint e) What is the magnitude of the electric field in the thick part of the wire? E2 =arrow_forwardplease helparrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning





