Explanation Given that: Electric resistance R = 8 Ω Potential V = 12 V Formula used: Write an expression for power. P = V 2 R ...... (1) Here, I is the current and R is the resistance of the circuit. Calculation: As the bulbs are connected in series and have equal resistance, so, the potential drop in the circuit is V d = 12 V 2 = 6 V . Substitute 6 V for V and 8 Ω for R in equation (1)

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ISBN: 9781260411393

Author: Tillery

Publisher: MCG COURSE

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Chapter 6, Problem 17PEA

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Power of the glowing bulbs.

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Chapter 6 Solutions

EBK PHYSICAL SCIENCE

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Power of the glowing bulbs.

Solution Summary: The author calculates the power of the glowing bulbs, based on a formula for calculating the potential drop in the circuit.

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