Describe the entity-relationship model. Represent the entities, relationships and attributes. Also, describe the approach for crow’s foot and cardinality in an E-R diagram.

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6.1 Consider silicon at 7 = 300 K that is doped with donor impurity atoms to a concentra- tion of Na = 5 x 105 cm³. The excess carrier lifetime is 2 x 10-'s. (a) Determine the thermal equilibrium recombination rate of holes. (b) Excess carriers are generated such that Sn = p = 104 cm³. What is the recombination rate of holes for this condition?

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Chapter 6, Problem 12RQ

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Describe the entity-relationship model. Represent the entities, relationships and attributes. Also, describe the approach for crow’s foot and cardinality in an E-R diagram.

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6.1 Consider silicon at 7 = 300 K that is doped with donor impurity atoms to a concentra- tion of Na = 5 x 105 cm³. The excess carrier lifetime is 2 x 10-'s. (a) Determine the thermal equilibrium recombination rate of holes. (b) Excess carriers are generated such that Sn = p = 104 cm³. What is the recombination rate of holes for this condition?

6.18 A semiconductor is uniformly doped with 107 cm³ acceptor atoms and has the fol- lowing properties: D = 27 cm²/s, D = 12 cm²/s, T = 5 × 10-7 s, and 7po = 10-7 s. An external source has been turned on for 1 <0 producing a uniform concentration of excess carriers at a generation rate of g = 10 cm³ s. The source turns off at time 1 = 0 and back on at time = 2 × 10-6 s. (a) Derive the expressions for the excess carrier concentration as a function of time for 01, (b) Determine the value of excess carrier concentration at (i) 1 = 0, (ii) 1 = 2 × 10-6 s, and (iii) t = x. (c) Plot the excess carrier concentration as a function of time.

What value is left in W0 (X0) after the following code is run (Remember ARMv8 is little endian)? SUB X4, X4, X4MOVZ X1, 0x1234, LSL 0ADD X2, XZR, XZRADD X10, XZR, XZRADD X0, XZR, XZRSTUR X1, [X2, 0]LDURB W0, [X2, 6] Note, STURB and LDURB operate on bytes instead of words. Also remember that W0 is the lower half of the X0 register. Write the answer in hex with a 0x in front and all leading 0's removed. It is not 0x0