Welding: Principles and Applications (MindTap Course List)
8th Edition
ISBN: 9781305494695
Author: Larry Jeffus
Publisher: Cengage Learning
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Chapter 6, Problem 12R
When stopping an SMA welding bead on a pipe, what should be done to make restarting it more uniform?
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Q4/ A compressor is driven motor by mean of a flat belt of thickness 10 mm and a width of
250 mm. The motor pulley is 300 mm diameter and run at 900 rpm and the compressor
pulley is 1500 mm diameter. The shaft center distance is 1.5 m. The angle of contact of
the smaller pulley is 220° and on the larger pulley is 270°. The coefficient of friction
between the belt and the small pulley is 0.3, and between the belt and the large pulley is
0.25. The maximum allowable belt stress is 2 MPa and the belt density is 970 kg/m³.
(a) What is the power capacity of the drive and (b) If the small pulley replaced by
V-grooved pulley of diameter 300 mm, grooved angle of 34° and the coefficient of
friction between belt and grooved pulley is 0.35. What will be the power capacity in this
case, assuming that the diameter of the large pulley remain the same of 1500 mm.
You are tasked with designing a power drive system to transmit power between a motor and a conveyor belt in a manufacturing facility as illustrated in figure.
The design must ensure efficient power transmission, reliability, and safety. Given the following specifications and constraints, design drive system for this application:
Specifications:
Motor Power: The electric motor provides 10 kW of power at 1,500 RPM.
Output Speed: The output shaft should rotate at 150 rpm.
Design Decisions:
Transmission ratio: Determine the necessary drive ratio for the system.
Shaft Diameter: Design the shafts for both the motor and the conveyor end.
Material Selection: Choose appropriate materials for the gears, shafts.
Bearings: Select suitable rolling element bearings.
Constraints:
Space Limitation:
The available space for the gear drive system is limited to a 1-meter-long section.
Attribute 4 of CEP
Depth of knowledge required
Fundamentals-based, first principles analytical approach…
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العنوان
In non-continuous dieless drawing process for copper tube as shown in Fig. (1), take the
following data: Do-20mm, to=3mm, D=12mm, ti/to=0.6 and v.-15mm/s. Calculate: (1)
area reduction RA, (2) drawing velocity v. Knowing that: ti: final thickness
V.
Fig. (1)
ofthre
Chapter 6 Solutions
Welding: Principles and Applications (MindTap Course List)
Ch. 6 - What is the first weld bead of a multiple pass...Ch. 6 - What is the purpose of using ceramic backup tapes...Ch. 6 - How can discontinuities in the root face be...Ch. 6 - Describe the motion of the electrode in keyhole...Ch. 6 - What is the purpose of placing an assembled test...Ch. 6 - If the key hole becomes smaller and smaller, what...Ch. 6 - What is the purpose of a hot pass?Ch. 6 - What are the best ways to remove slag between...Ch. 6 - What is the last weld bead on a multipass weld...Ch. 6 - What is the purpose of grooving a joint before...
Ch. 6 - After a weld is back gouged and a groove is...Ch. 6 - When stopping an SMA welding bead on a pipe, what...Ch. 6 - What is the purpose of preheating metal before it...Ch. 6 - What is the purpose of postheating the metal after...Ch. 6 - What is interpass temperature?Ch. 6 - The AWS Visual Inspection Criteria allows one...Ch. 6 - What is the difference between a transverse face...Ch. 6 - What changes can be made to successfully make a...
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