
Concept explainers
you can use the concepts in this chapter to obtain an estimate of the number of atoms in the universe. These steps will guide you through this calculation.
a. Begin by calculating the number of atoms in the sun. Assume that the sun is pure hydrogen with a density of
b. The sun is an average-sized star, and stars are believed to compose most of the mass of the visible universe (planets are so small they can be ignored), so we can estimate the number of atoms in a galaxy by assuming that every star in the galaxy has the same number of atoms as our sun. The Milky Way galaxy is believed to contain
c. Astronomers estimate that the universe contains approximately
Our sun is one of the 100 billion stars in the Milky Way galaxy. The universe is estimated to contain about 100 billion galaxies.

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Chapter 6 Solutions
Introducing Chemistry
- Please do these questions within the SCH4U course please with full steps since I am still unsure how to format my answers! Thank you so much.arrow_forwardWhen two solutions, one of 0.1 M KCl (I) and the other of 0.1 M MCl (II), are brought into contact by a membrane. The cation M cannot cross the membrane. At equilibrium, x moles of K+ will have passed from solution (I) to (II). To maintain the neutrality of the two solutions, x moles of Cl- will also have to pass from I to II. Explain this equality: (0.1 - x)/x = (0.1 + x)/(0.1 - x)arrow_forwardCalculate the variation in the potential of the Pt/MnO4-, Mn2+ pair with pH, indicating the value of the standard potential. Data: E0 = 1.12.arrow_forward
- Given the cell: Pt l H2(g) l dis X:KCl (sat) l Hg2Cl2(s) l Hg l Pt. Calculate the emf of the cell as a function of pH.arrow_forwardThe decimolar calomel electrode has a potential of 0.3335 V at 25°C compared to the standard hydrogen electrode. If the standard reduction potential of Hg22+ is 0.7973 V and the solubility product of Hg2Cl2 is 1.2x 10-18, find the activity of the chlorine ion at this electrode.Data: R = 8.314 J K-1 mol-1, F = 96485 C mol-1, T = 298.15 K.arrow_forward2. Add the following group of numbers using the correct number of significant figures for the answer. Show work to earn full credit such as rounding off the answer to the correct number of significant figures. Replace the question marks with the calculated answers or write the calculated answers near the question marks. 10916.345 37.40832 5.4043 3.94 + 0.0426 ? (7 significant figures)arrow_forward
- The emf at 25°C of the cell: Pt l H2(g) l dis X:KCl (sat) l Hg2Cl2(s) l Hg l Pt was 612 mV. When solution X was replaced by normal phosphate buffer solution with a pH of 6.86, the emf was 741 mV. Calculate the pH of solution X.arrow_forwardIndicate how to calculate the potential E of the reaction Hg2Cl2(s) + 2e ⇄ 2Hg + 2Cl- as a function of the concentration of Cl- ions. Data: the solubility product of Hg2Cl2.arrow_forwardHow can Beer’s Law be used to determine the concentration in a selected food sample. Provide an in-depth discussion and examples of this.arrow_forward
- b) H3C- H3C Me CH 3 I HN Me H+arrow_forwardUsing Luther's rule, determine the reference potentials of the electrodes corresponding to the low stability systems Co³+/Co and Cr²+/Cr from the data in the table. Electrodo ΕΝ Co²+/Co Co3+/Co²+ -0,28 +1,808 Cr³+ / Cr -0,508 Cr3+ / Cr²+ -0,41arrow_forwardThe molecule PYRIDINE, 6tt electrons and is there pore aromuntre and is Assigned the Following structure contenus Since aromatk moleculey undergo electrophilic allomatic substitution, Pyridine should undergo The Following reaction + HNO3 12504 a. write all of the possible Mononitration Products that could Result From this roaction Based upon the reaction the reaction mechanism determine which of these producty would be the major Product of the hegetionarrow_forward
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