a. Justification: Normally, the primary key, foreign key and not null constraints are used to enforce total participation constraints on a many-to-many relationship on the relations created from the relationship. However, in Structured Query Language (SQL) total participation constraints on a many-to-many relationship can’t be enforced on the relations created from the relationship because, they have to be embodied as separate relation that will not be combined with either of the participating entities...

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Answer 1

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Chapter 6, Problem 11PE

Explanation of Solution

a.

Justification:

Normally, the primary key, foreign key and not null constraints are used to enforce total participation constraints on a many-to-many relationship on the relations created from the relationship.

However, in Structured Query Language (SQL) total participation constraints on a many-to-many relationship can’t be enforced on the relations created from the relationship because, they have to be embodied as separate relation that will not be combined with either of the participating entities...

Explanation of Solution

b.

Enforcing total participation constraints using complex check constraints or assertions:

For a many-to-one relation R from entity “A” to “B” with their respective primary keys as “a” and “b”, the below constraints can be applied on relation “B”...

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Can you help me solve this problem using Master's Theorem:Solve the recurrence relation f(n) = 3af(n/a) + (n + a)2 with f(1) = 1 and a > 1 byfinding an expression for f(n) in big-Oh notation.

here is example 7.6## Example 7.6 Suppose the sample population is χ 2 (2), which is non-normal but with same variance 4. ▶ Repeat the simulation, but replacing the N(0, 4) samples with χ 2 (2) samples. ▶ Calculate the empirical confidence level.(Empirical confidence level) n <- 20 alpha <- 0.05 UCL <- replicate(1000, expr = { x <- rchisq(n,df=2) (n-1)*var(x)/qchisq(alpha,df=n-1) }) sum(UCL >4) mean(UCL > 4) ## t.test function n <- 20 x <- rnorm(n,mean=2) result <- t.test(x,mu=1) result$statistic result$parameter result$p.value result$conf.int result$estimate

using r language

Answer 2

Expert Solution & Answer

Chapter 6, Problem 11PE

Explanation of Solution

a.

Justification:

Normally, the primary key, foreign key and not null constraints are used to enforce total participation constraints on a many-to-many relationship on the relations created from the relationship.

However, in Structured Query Language (SQL) total participation constraints on a many-to-many relationship can’t be enforced on the relations created from the relationship because, they have to be embodied as separate relation that will not be combined with either of the participating entities...

Explanation of Solution

b.

Enforcing total participation constraints using complex check constraints or assertions:

For a many-to-one relation R from entity “A” to “B” with their respective primary keys as “a” and “b”, the below constraints can be applied on relation “B”...

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 3

Expert Solution & Answer

Chapter 6, Problem 11PE

Explanation of Solution

a.

Justification:

Normally, the primary key, foreign key and not null constraints are used to enforce total participation constraints on a many-to-many relationship on the relations created from the relationship.

However, in Structured Query Language (SQL) total participation constraints on a many-to-many relationship can’t be enforced on the relations created from the relationship because, they have to be embodied as separate relation that will not be combined with either of the participating entities...

Explanation of Solution

b.

Enforcing total participation constraints using complex check constraints or assertions:

For a many-to-one relation R from entity “A” to “B” with their respective primary keys as “a” and “b”, the below constraints can be applied on relation “B”...

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 6, Problem 11PE

Explanation of Solution

a.

Justification:

Normally, the primary key, foreign key and not null constraints are used to enforce total participation constraints on a many-to-many relationship on the relations created from the relationship.

However, in Structured Query Language (SQL) total participation constraints on a many-to-many relationship can’t be enforced on the relations created from the relationship because, they have to be embodied as separate relation that will not be combined with either of the participating entities...

Explanation of Solution

b.

Enforcing total participation constraints using complex check constraints or assertions:

For a many-to-one relation R from entity “A” to “B” with their respective primary keys as “a” and “b”, the below constraints can be applied on relation “B”...

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Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 6, Problem 11PE

Explanation of Solution

a.

Justification:

Normally, the primary key, foreign key and not null constraints are used to enforce total participation constraints on a many-to-many relationship on the relations created from the relationship.

However, in Structured Query Language (SQL) total participation constraints on a many-to-many relationship can’t be enforced on the relations created from the relationship because, they have to be embodied as separate relation that will not be combined with either of the participating entities...

Explanation of Solution

b.

Enforcing total participation constraints using complex check constraints or assertions:

For a many-to-one relation R from entity “A” to “B” with their respective primary keys as “a” and “b”, the below constraints can be applied on relation “B”...

Answer 8

Chapter 6, Problem 11PE

Explanation of Solution

a.

Justification:

Normally, the primary key, foreign key and not null constraints are used to enforce total participation constraints on a many-to-many relationship on the relations created from the relationship.

However, in Structured Query Language (SQL) total participation constraints on a many-to-many relationship can’t be enforced on the relations created from the relationship because, they have to be embodied as separate relation that will not be combined with either of the participating entities...

Answer 9

Chapter 6, Problem 11PE

Explanation of Solution

a.

Justification:

Normally, the primary key, foreign key and not null constraints are used to enforce total participation constraints on a many-to-many relationship on the relations created from the relationship.

However, in Structured Query Language (SQL) total participation constraints on a many-to-many relationship can’t be enforced on the relations created from the relationship because, they have to be embodied as separate relation that will not be combined with either of the participating entities...

Answer 10

Explanation of Solution

b.

Enforcing total participation constraints using complex check constraints or assertions:

For a many-to-one relation R from entity “A” to “B” with their respective primary keys as “a” and “b”, the below constraints can be applied on relation “B”...

Answer 11

Explanation of Solution

b.

Enforcing total participation constraints using complex check constraints or assertions:

For a many-to-one relation R from entity “A” to “B” with their respective primary keys as “a” and “b”, the below constraints can be applied on relation “B”...

Answer 12

Expert Solution & Answer

Answer 13

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Answer 14

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Answer 15

Ch. 6 - Prob. 1PE Ch. 6 - Consider a database that includes the entity sets...Ch. 6 - Design an E-R diagram for keeping track of the...Ch. 6 - Prob. 4PE Ch. 6 - Prob. 5PE Ch. 6 - Prob. 6PE Ch. 6 - Prob. 7PE Ch. 6 - Consider a relation such as sec_course, generated...Ch. 6 - Suppose the advisor relationship set were...Ch. 6 - Prob. 10PE

Explanation of Solution

Explanation of Solution

b. Enforcing total participation constraints using complex check constraints or assertions: For a many-to-one relation R from entity “A” to “B” with their respective primary keys as “a” and “b”, the below constraints can be applied on relation “B”...

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Chapter 6 Solutions

b.

Enforcing total participation constraints using complex check constraints or assertions:

For a many-to-one relation R from entity “A” to “B” with their respective primary keys as “a” and “b”, the below constraints can be applied on relation “B”...