Given the following data Fe 2 O 3 ( s ) + 3 CO ( g ) → 2 Fe ( s ) + 3 CO 2 ( g ) Δ H ° = − 23 KJ 3 Fe 2 O 3 ( s ) + CO ( g ) → 2 Fe 3 O 4 ( s ) + CO 2 ( g ) Δ H ° = − 39 KJ Fe 3 O 4 ( s ) + CO ( g ) → 3 FeO ( s ) + CO 2 ( g ) Δ H ° = 18 KJ Calculate ∆ H° for this reaction FeO ( s ) + CO ( g ) → Fe ( s ) + CO 2 ( g )
Given the following data Fe 2 O 3 ( s ) + 3 CO ( g ) → 2 Fe ( s ) + 3 CO 2 ( g ) Δ H ° = − 23 KJ 3 Fe 2 O 3 ( s ) + CO ( g ) → 2 Fe 3 O 4 ( s ) + CO 2 ( g ) Δ H ° = − 39 KJ Fe 3 O 4 ( s ) + CO ( g ) → 3 FeO ( s ) + CO 2 ( g ) Δ H ° = 18 KJ Calculate ∆ H° for this reaction FeO ( s ) + CO ( g ) → Fe ( s ) + CO 2 ( g )
Solution Summary: The author explains the standard enthalpy change, which is calculated by using given data.
Fe
2
O
3
(
s
)
+
3
CO
(
g
)
→
2
Fe
(
s
)
+
3
CO
2
(
g
)
Δ
H
°
=
−
23
KJ
3
Fe
2
O
3
(
s
)
+
CO
(
g
)
→
2
Fe
3
O
4
(
s
)
+
CO
2
(
g
)
Δ
H
°
=
−
39
KJ
Fe
3
O
4
(
s
)
+
CO
(
g
)
→
3
FeO
(
s
)
+
CO
2
(
g
)
Δ
H
°
=
18
KJ
Decide whether these proposed Lewis structures are reasonable.
proposed Lewis structure
Yes.
Is the proposed Lewis structure reasonable?
Cl-
: 2:
:Z:
:Z:
N—N
: 0:
C C1:
O CO
No, it has the wrong number of valence electrons.
The correct number is: ☐
No, it has the right number of valence electrons but doesn't satisfy the
octet rule.
The symbols of the problem atoms are:* ☐
Yes.
No, it has the wrong number of valence electrons.
The correct number is: ☐
No, it has the right number of valence electrons but doesn't satisfy the
octet rule.
The symbols of the problem atoms are:* |
Yes.
No, it has the wrong number of valence electrons.
The correct number is:
No, it has the right number of valence electrons but doesn't satisfy the
octet rule.
The symbols of the problem atoms are:* |
If two or more atoms of the same element don't satisfy the octet rule, just enter the chemical symbol as many
times as necessary. For example, if two oxygen atoms don't satisfy the octet rule, enter "0,0".
☑
Use the observations about each chemical reaction in the table below to decide the sign (positive or negative) of the reaction enthalpy AH and reaction entropy
AS.
Note: if you have not been given enough information to decide a sign, select the "unknown" option.
reaction
observations
conclusions
ΔΗ is
(pick one)
A
This reaction is faster above 103. °C than
below.
AS is
(pick one)
ΔΗ is
(pick one)
B
This reaction is spontaneous only above
-9. °C.
AS is
(pick one)
ΔΗ is
(pick one)
C
The reverse of this reaction is always
spontaneous.
AS is
(pick one)
18
Ar
Use the observations about each chemical reaction in the table below to decide the sign (positive or negative) of the reaction enthalpy AH and reaction entropy
AS.
Note: if you have not been given enough information to decide a sign, select the "unknown" option.
reaction
observations
conclusions
A
The reverse of this reaction is always
spontaneous but proceeds slower at
temperatures below 41. °C.
ΔΗ is
(pick one)
AS is
(pick one)
ΔΗ is
(pick one)
B
This reaction is spontaneous except above
94. °C.
AS is
(pick one)
This reaction is always spontaneous, but
ΔΗ is
(pick one)
C
proceeds slower at temperatures below
−14. °C.
AS is
(pick one)
Х
00.
18
Ar
무ㅎ
B
1
1
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