Statistics for Engineers and Scientists
Statistics for Engineers and Scientists
4th Edition
ISBN: 9780073401331
Author: William Navidi Prof.
Publisher: McGraw-Hill Education
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Textbook Question
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Chapter 5.8, Problem 1E

Find the following values.

  1. a. χ 12 , .025 2
  2. b. χ 12 , .975 2
  3. c. χ 5 , .055 2
  4. d. χ 5 , .995 2
  5. e. χ 22 , .1 2
  6. f. χ 22 , .9 2

a.

Expert Solution
Check Mark
To determine

Find the value of χ12,0.0252.

Answer to Problem 1E

The value of χ12,0.0252 is 23.34.

Explanation of Solution

Calculation:

Software Procedure:

Step-by-step procedure to obtain the critical value using the MINITAB software:

  • Choose Graph > Probability Distribution Plot choose View Probability> OK.
  • From Distribution, choose ‘chi square distribution.
  • In Degrees of freedom, enter 12.
  • Click the Shaded Area tab.
  • Choose Probability Value and Right Tail for the region of the curve to shade.
  • Enter the Probability value as 0.025.
  • Click OK.

Output using the MINITAB software is given below:

Statistics for Engineers and Scientists, Chapter 5.8, Problem 1E , additional homework tip  1

From the output, the value of χ12,0.0252 is 23.34.

b.

Expert Solution
Check Mark
To determine

Find the value of χ12,0.9752.

Answer to Problem 1E

The value of χ12,0.9752 is 4.404.

Explanation of Solution

Calculation:

Software Procedure:

Step-by-step procedure to obtain the critical value using the MINITAB software:

  • Choose Graph > Probability Distribution Plot choose View Probability> OK.
  • From Distribution, choose ‘chi square distribution.
  • In Degrees of freedom, enter 12.
  • Click the Shaded Area tab.
  • Choose Probability Value and Right Tail for the region of the curve to shade.
  • Enter the Probability value as 0.975.
  • Click OK.

Output using the MINITAB software is given below:

Statistics for Engineers and Scientists, Chapter 5.8, Problem 1E , additional homework tip  2

From the output, the value of χ12,0.9752 is 4.404.

c.

Expert Solution
Check Mark
To determine

Find the value of χ5,0.0052.

Answer to Problem 1E

The value of χ5,0.0052 is 16.75.

Explanation of Solution

Calculation:

Software Procedure:

Step-by-step procedure to obtain the critical value using the MINITAB software:

  • Choose Graph > Probability Distribution Plot choose View Probability> OK.
  • From Distribution, choose ‘chi square distribution.
  • In Degrees of freedom, enter 5.
  • Click the Shaded Area tab.
  • Choose Probability Value and Right Tail for the region of the curve to shade.
  • Enter the Probability value as 0.005.
  • Click OK.

Output using the MINITAB software is given below:

Statistics for Engineers and Scientists, Chapter 5.8, Problem 1E , additional homework tip  3

From the output, the value of χ5,0.0052 is 16.75.

d.

Expert Solution
Check Mark
To determine

Find the value of χ5,0.9952.

Answer to Problem 1E

The value of χ5,0.9952 is 0.4117.

Explanation of Solution

Calculation:

Software Procedure:

Step-by-step procedure to obtain the critical value using the MINITAB software:

  • Choose Graph > Probability Distribution Plot choose View Probability> OK.
  • From Distribution, choose ‘chi square distribution.
  • In Degrees of freedom, enter 5.
  • Click the Shaded Area tab.
  • Choose Probability Value and Right Tail for the region of the curve to shade.
  • Enter the Probability value as 0.995.
  • Click OK.

Output using the MINITAB software is given below:

Statistics for Engineers and Scientists, Chapter 5.8, Problem 1E , additional homework tip  4

From the output, the value of χ5,0.9952 is 0.4117.

e.

Expert Solution
Check Mark
To determine

Find the value of χ22,0.12.

Answer to Problem 1E

The value of χ22,0.12 is 30.81.

Explanation of Solution

Calculation:

Software Procedure:

Step-by-step procedure to obtain the critical value using the MINITAB software:

  • Choose Graph > Probability Distribution Plot choose View Probability> OK.
  • From Distribution, choose ‘chi square distribution.
  • In Degrees of freedom, enter 22.
  • Click the Shaded Area tab.
  • Choose Probability Value and Right Tail for the region of the curve to shade.
  • Enter the Probability value as 0.1.
  • Click OK.

Output using the MINITAB software is given below:

Statistics for Engineers and Scientists, Chapter 5.8, Problem 1E , additional homework tip  5

From the output, the value of χ22,0.12 is 30.81.

f.

Expert Solution
Check Mark
To determine

Find the value of χ22,0.92.

Answer to Problem 1E

The value of χ22,0.92 is 14.04.

Explanation of Solution

Calculation:

Software Procedure:

Step-by-step procedure to obtain the critical value using the MINITAB software:

  • Choose Graph > Probability Distribution Plot choose View Probability> OK.
  • From Distribution, choose ‘chi square distribution.
  • In Degrees of freedom, enter 22.
  • Click the Shaded Area tab.
  • Choose Probability Value and Right Tail for the region of the curve to shade.
  • Enter the Probability value as 0.9.
  • Click OK.

Output using the MINITAB software is given below:

Statistics for Engineers and Scientists, Chapter 5.8, Problem 1E , additional homework tip  6

From the output, the value of χ22,0.92 is 14.04.

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Chapter 5 Solutions

Statistics for Engineers and Scientists

Ch. 5.1 - The sugar content in a one-cup serving of a...Ch. 5.1 - Refer to Exercise 5. a. Find a 95% lower...Ch. 5.1 - Prob. 13ECh. 5.1 - Prob. 14ECh. 5.1 - Prob. 15ECh. 5.1 - Refer to Exercise 9. a. Find a 90% upper...Ch. 5.1 - Refer to Exercise 10. a. Find a 98% lower...Ch. 5.1 - Refer to Exercise 11. a. Find a 95% upper...Ch. 5.1 - Prob. 19ECh. 5.1 - A 95% confidence interval for a population mean is...Ch. 5.1 - Based on a large sample of capacitors of a certain...Ch. 5.1 - Sixty-four independent measurements were made of...Ch. 5.1 - A large box contains 10,000 ball bearings. A...Ch. 5.1 - Prob. 24ECh. 5.1 - Prob. 25ECh. 5.1 - Prob. 26ECh. 5.2 - In a simple random sample of 70 automobiles...Ch. 5.2 - During a recent drought, a water utility in a...Ch. 5.2 - A soft-drink manufacturer purchases aluminum cans...Ch. 5.2 - The article HIV-positive Smokers Considering...Ch. 5.2 - The article The Functional Outcomes of Total Knee...Ch. 5.2 - Refer to Exercise 1. 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A...Ch. 5.8 - Prob. 6ECh. 5.8 - Boxes of cereal are labeled as containing 14...Ch. 5.8 - Prob. 8ECh. 5.8 - Following are interest rates (annual percentage...Ch. 5.8 - Prob. 10ECh. 5.8 - Prob. 11ECh. 5.8 - Prob. 12ECh. 5.9 - A sample of 25 resistors, each labeled 100, had an...Ch. 5.9 - Prob. 2ECh. 5.9 - The article Ozone for Removal of Acute Toxicity...Ch. 5.9 - Six measurements were made of the concentration...Ch. 5.9 - Five measurements are taken of the octane rating...Ch. 5 - A molecular biologist is studying the...Ch. 5 - Prob. 2SECh. 5 - The article Genetically Based Tolerance to...Ch. 5 - A sample of 87 glass sheets has a mean thickness...Ch. 5 - Prob. 5SECh. 5 - Prob. 6SECh. 5 - Leakage from underground fuel tanks has been a...Ch. 5 - Prob. 8SECh. 5 - Prob. 9SECh. 5 - Prob. 10SECh. 5 - In the article Groundwater Electromagnetic Imaging...Ch. 5 - Prob. 12SECh. 5 - Prob. 13SECh. 5 - Prob. 14SECh. 5 - A metallurgist makes several measurements of the...Ch. 5 - In a study of the lifetimes of electronic...Ch. 5 - The temperature of a certain solution is estimated...Ch. 5 - Prob. 18SECh. 5 - Prob. 19SECh. 5 - The answer to Exercise 19 part (d) is needed for...Ch. 5 - The carbon content (in ppm) was measured for each...Ch. 5 - Diameters, in mm, were measured for eight...Ch. 5 - A sample of eight repair records for a certain...Ch. 5 - Prob. 25SE
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