COMPUTER SYSTEMS&MOD MSGT/ET SA AC PKG
3rd Edition
ISBN: 9780134671123
Author: Bryant
Publisher: PEARSON
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Chapter 5.7, Problem 5.6PP
Practice Problem 5.6 (solution page 575)
Let us continue exploring ways to evaluate polynomials, as described in Practice Problem 5 5. We can reduce the number of multiplications in evaluating a polynomial by applying Horner’s method, named after British mathematician William G. Horner (1786-1837). The idea is to repeatedly factor out the powers of x to get the following evaluation:
a0+x(a1+x(a2+···x(an-1+xan)···)) (5.3)
Using Horner's method, we can implement polynomial evaluation using the following code:
- A. For degree n, how many additions and how many multiplications does this code perform?
- B. On our reference machine, with the arithmetic operations having the latencies shown in Figure 5.12, we measure the CPE for this function to be 8.00. Explain how this CPE arises based on the data dependencies formed between iterations due to the operations implementing line 7 of the function.
- C. Explain how the function shown in Practice Problem 5.5 can run faster, even though it requires more operations.
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1. (The MyRoot method) Below is a manual implementation of the Math.sqrt() method in Java.
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public class SquareRoot {
public static void main(String[] args) {
}
// implement a loop of your choice here
// Method that calculates the square root of integer variables
public static double myRoot(int number) {
double root;
root=number/2;
double root old;
do {
root old root;
root (root_old+number/root_old)/2;
} while (Math.abs(root_old-root)>1.8E-6);
return root;
}
// Method that calculates the square root of double variables
public static double myRoot(double number) {
double root;
root number/2;
double root_old;
do {
root old root;
root (root_old+number/root_old)/2;
while (Math.abs (root_old-root)>1.0E-6);
return root;
}
}
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