Explanation Given The stated reaction is, 2 H 2 O 2 ( l ) → 2 H 2 O ( l ) + O 2 ( g ) The standard enthalpy of formation of one mole of H 2 O 2 ( l ) is − 187.8 kJ / mol . The standard enthalpy of formation of the given two moles of H 2 O 2 ( l ) is − ( 2 × 187.8 ) kJ / mol . The standard enthalpy of formation of one mole of H 2 O ( l ) is − 285.5 kJ / mol . The standard enthalpy of formation of the given two moles of H 2 O ( l ) is − ( 2 × 285.5 ) kJ / mol . The value of the standard enthalpy of formation of an element is zero. Hence, the standard enthalpy of formation of O 2 is zero. The enthalpy change of the reaction is calculated by the formula,] Δ H r e a c t i o n ° = ∑ n Δ H f ° ( products ) − ∑ m Δ H f ° ( reactancts ) = [ 2 Δ H f ° ( H 2 O ) + Δ H f ° (

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Chapter 5.7, Problem 5.11.1PE

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To determine: The enthalpy change for the given reaction.

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Chapter 5.7, Problem 5.10.2PE

Chapter 5.7, Problem 5.11.2PE

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