Electric Motor Control
10th Edition
ISBN: 9781133702818
Author: Herman
Publisher: CENGAGE L
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Question
Chapter 57, Problem 1SQ
To determine
Explain about the base speed of a DC motor.
Expert Solution & Answer
Explanation of Solution
Discussion:
The base speed of a DC motor is the speed attained by a motor at rated armature voltage, rated load current, and rate field current.
The motor operates below base speed when the armature voltage is reduced. The torque of the shunt motor remains constant at below base speed. The motor operates above base speed when the field current is reduced.
Conclusion:
Thus, the base speed of a DC motor is explained.
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Students have asked these similar questions
For the circuit shown, let V₁ = 12 V, Is1 = 2A, Is2 = 4A, R₁ = 2, R2 = 4, and R3 = 6. Determine the current
Io using Mesh method as follows:
1. Choose all meshes that must be included, if any, to construct the supermesh.
11, 13
O 11, 12
O 12, 13, 11
12, 13
O none of the above
2. Consider mesh (loop) iz, write the corresponding expression in terms of mesh currents i₁, 12, 13 as
of the form (R11 · i₁ + R₁2 · 2 + R₁3-13 = V₁), then enter the corresponding values:
R11
R12
R13
Ω
Ω
Ω
V
V₁₂
3. Solve the above equation to determine then lo :
10
=
Ist
A
R₁
ww
ww
R₂
+
V₁
1,
R3
The relative tolerance for this problem is 7%.
ww
IS2
Enter the matrix values (numerical) to solve for mesh-currents i₁, iz and 13, for the circuit shown, using
Mesh method. In the matrix, row 1, row 2, and row 3 correspond to i₁, 12 and 13, current expressions,
respectively. Let Vs=15, R₁ =50, R₂-32, R3-8, R4-17, R5-29, and R=41.
[R11 R12 R13
The matrix values are shown here: R21 R22 R23
= V₂
R31 R32 R33
[V3]
The relative tolerance for this problem is 5%.
R1
Loop i₁
R11
+
Vs
Ω
R12
Ω
R13
Ω
V
V₁=
Loop 12
R21
Ω
R22
Ω
R23
Ω
V
V₂
Loop 13
Ω
R31
R32
Ω
R33
Ω
V3=
V
R2
R4
R3
R5
R6
For circuit shown, use Mesh method to find the voltage Vo as follows. Enter, in the matrix format, as
below, the loop currents, where row 1, and row 2, correspond to i₁, and i2 loop current expressions,
respectively. Let Vs1-5, Vs2-15, R₁=5, R₂=2, and R3=8.
The matrix values are shown here:
[R11 R12 21
R21 R22
Rx - M - M
iz
=
The relative tolerance for this problem is 5%.
Vst
(+-
R1
ww
Loop i₁
R115
G12
V₁ =
Loop 12
R21
R22
V₂=
Ω
C C
Ω
V
Ω
02
C
V
R₂
ww
VS2
+
Ry
ww
+
Vo
Use Cramer's rule (matrix), substitution, or any other method to calculate the voltages:
Chapter 57 Solutions
Electric Motor Control
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