Advanced Mathematical Concepts: Precalculus with Applications, Student Edition

1st Edition

ISBN: 9780078682278

Author: McGraw-Hill, Berchie Holliday

Publisher: Glencoe/McGraw-Hill

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Concept explainers

Ratios

A ratio is a comparison between two numbers of the same kind. It represents how many times one number contains another. It also represents how small or large one number is compared to the other.

Trigonometric Ratios

Trigonometric ratios give values of trigonometric functions. It always deals with triangles that have one angle measuring 90 degrees. These triangles are right-angled. We take the ratio of sides of these triangles.

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Question

Chapter 5.7, Problem 10CFU

(a)

To determine

To Draw: The figure that illustrate the situation.

(a)

Expert Solution

Explanation of Solution

Given:A vertical tower is located on the top of the hill that has an angle of elevation of 10° .A 70−foot guy wire is attached to the tower 45−foot above the hill.

The figure that illustrate the situation is shown below.

Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 5.7, Problem 10CFU , additional homework tip 1

(b)

To determine

To Find: What angle does the guy wire make with the side of the hill.

(b)

Expert Solution

Answer to Problem 10CFU

x≈39.3°

Explanation of Solution

Given:A vertical tower is located on the top of the hill that has an angle of elevation of 10° .A 70−foot guy wire is attached to the tower 45−foot above the hill.

Here in the lower triangle.

90°−10°=80°180°−80°=100°

Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 5.7, Problem 10CFU , additional homework tip 2

Using the law of sine

70sin100°=45sinx°x=sin−1(45sin100°70)x≈39.3°

(c)

To determine

To Find:How far from the base of the tower is the guy wire anchored to the hill?

(c)

Expert Solution

Answer to Problem 10CFU

46.4 ft

Explanation of Solution

Given:A vertical tower is located on the top of the hill that has an angle of elevation of 10° .A 70−foot guy wire is attached to the tower 45−foot above the hill.

Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 5.7, Problem 10CFU , additional homework tip 3

x≈39.3°

Thus

θ=180°−(100°−39.3°)=40.7°ysin40.7°=70sin100°y=70sin40.7°sin100°y≈46.4 ft

Chapter 5.7, Problem 9CFU

Chapter 5.7, Problem 11E

Chapter 5 Solutions

Advanced Mathematical Concepts: Precalculus with Applications, Student Edition

Ch. 5.1 - Prob. 1CFU Ch. 5.1 - Prob. 2CFU Ch. 5.1 - Prob. 3CFU Ch. 5.1 - Prob. 4CFU Ch. 5.1 - Prob. 5CFU Ch. 5.1 - Prob. 6CFU Ch. 5.1 - Prob. 7CFU Ch. 5.1 - Prob. 8CFU Ch. 5.1 - Prob. 9CFU Ch. 5.1 - Prob. 10CFU

Ch. 5.1 - Prob. 11CFU Ch. 5.1 - Prob. 12CFU Ch. 5.1 - Prob. 13CFU Ch. 5.1 - Prob. 14CFU Ch. 5.1 - Prob. 15CFU Ch. 5.1 - Prob. 16CFU Ch. 5.1 - Prob. 17CFU Ch. 5.1 - Prob. 18E Ch. 5.1 - Prob. 19E Ch. 5.1 - Prob. 20E Ch. 5.1 - Prob. 21E Ch. 5.1 - Prob. 22E Ch. 5.1 - Prob. 23E Ch. 5.1 - Prob. 24E Ch. 5.1 - Prob. 25E Ch. 5.1 - Prob. 26E Ch. 5.1 - Prob. 27E Ch. 5.1 - Prob. 28E Ch. 5.1 - Prob. 29E Ch. 5.1 - Prob. 30E Ch. 5.1 - Prob. 31E Ch. 5.1 - Prob. 32E Ch. 5.1 - Prob. 33E Ch. 5.1 - Prob. 34E Ch. 5.1 - Prob. 35E Ch. 5.1 - Prob. 36E Ch. 5.1 - Prob. 37E Ch. 5.1 - Prob. 38E Ch. 5.1 - Prob. 39E Ch. 5.1 - Prob. 40E Ch. 5.1 - Prob. 41E Ch. 5.1 - Prob. 42E Ch. 5.1 - Prob. 43E Ch. 5.1 - Prob. 44E Ch. 5.1 - Prob. 45E Ch. 5.1 - Prob. 46E Ch. 5.1 - Prob. 47E Ch. 5.1 - Prob. 48E Ch. 5.1 - Prob. 49E Ch. 5.1 - Prob. 50E Ch. 5.1 - Prob. 51E Ch. 5.1 - Prob. 52E Ch. 5.1 - Prob. 53E Ch. 5.1 - Prob. 54E Ch. 5.1 - Prob. 55E Ch. 5.1 - Prob. 56E Ch. 5.1 - Prob. 57E Ch. 5.1 - Prob. 58E Ch. 5.1 - Prob. 59E Ch. 5.1 - 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