a. Explanation Formula used: Derivative exponent rule, d d x ( a x ) = a x ln ( a ) Calculation: The book value of the assets at the end of n years, is given by V ( n ) = C ( 1 − 2 N ) n where, initial value of the asset in dollars and N is the number of years over which the asset is depreciated. Use the above derivative exponent rule and differentiate V ( n ) as follows b. To determine The relative change of V ( n ) = C ( 1 − 2 N ) n .

Applied Calculus for the Managerial, Life, and Social Sciences

10th Edition

ISBN: 9781305887831

Author: Tan

Publisher: CENGAGE CO

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Chapter 5.5, Problem 75E

To determine

The derivative of V(n)=C(1−2N)n.

To determine

The relative change of V(n)=C(1−2N)n.

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Chapter 5.5, Problem 74E

Chapter 5.5, Problem 76E

Chapter 5 Solutions

Applied Calculus for the Managerial, Life, and Social Sciences

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Prob. 24E Ch. 5.5 - Prob. 25E Ch. 5.5 - Prob. 26E Ch. 5.5 - Prob. 27E Ch. 5.5 - find the derivative of the function. 28...Ch. 5.5 - Prob. 29E Ch. 5.5 - Prob. 30E Ch. 5.5 - Prob. 31E Ch. 5.5 - Prob. 32E Ch. 5.5 - Prob. 33E Ch. 5.5 - Prob. 34E Ch. 5.5 - Prob. 35E Ch. 5.5 - Prob. 36E Ch. 5.5 - Prob. 37E Ch. 5.5 - Prob. 38E Ch. 5.5 - Prob. 39E Ch. 5.5 - Prob. 40E Ch. 5.5 - Prob. 41E Ch. 5.5 - Prob. 42E Ch. 5.5 - Prob. 43E Ch. 5.5 - Prob. 44E Ch. 5.5 - Prob. 45E Ch. 5.5 - Prob. 46E Ch. 5.5 - Prob. 47E Ch. 5.5 - Prob. 48E Ch. 5.5 - Prob. 49E Ch. 5.5 - Prob. 50E Ch. 5.5 - Prob. 51E Ch. 5.5 - Prob. 52E Ch. 5.5 - Prob. 53E Ch. 5.5 - Prob. 54E Ch. 5.5 - Prob. 55E Ch. 5.5 - Prob. 56E Ch. 5.5 - Prob. 57E Ch. 5.5 - Prob. 58E Ch. 5.5 - Prob. 59E Ch. 5.5 - Prob. 60E Ch. 5.5 - Prob. 61E Ch. 5.5 - Prob. 62E Ch. 5.5 - Prob. 63E Ch. 5.5 - Prob. 64E Ch. 5.5 - Prob. 65E Ch. 5.5 - Prob. 66E Ch. 5.5 - Prob. 67E Ch. 5.5 - Prob. 68E Ch. 5.5 - Prob. 69E Ch. 5.5 - Prob. 70E Ch. 5.5 - Prob. 71E Ch. 5.5 - Prob. 72E Ch. 5.5 - 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Prob. 17E Ch. 5.6 - Prob. 18E Ch. 5.6 - DEMAND FOR COMPUTERS Universal Instruments found...Ch. 5.6 - Prob. 20E Ch. 5.6 - Prob. 21E Ch. 5.6 - Prob. 22E Ch. 5.6 - GROWTH OF A FRUIT FLY POPULATION On the basis of...Ch. 5.6 - Prob. 24E Ch. 5.6 - Prob. 25E Ch. 5.6 - Prob. 26E Ch. 5.6 - Prob. 27E Ch. 5.6 - Prob. 28E Ch. 5.6 - Prob. 29E Ch. 5.6 - Prob. 30E Ch. 5.6 - Prob. 31E Ch. 5.6 - Prob. 32E Ch. 5.6 - Prob. 33E Ch. 5.6 - Prob. 34E Ch. 5.6 - Prob. 35E Ch. 5.6 - Prob. 36E Ch. 5.6 - Prob. 37E Ch. 5.6 - Prob. 38E Ch. 5.6 - Prob. 1TE Ch. 5.6 - Prob. 2TE Ch. 5.6 - Prob. 3TE Ch. 5.6 - Prob. 4TE Ch. 5.6 - Prob. 5TE Ch. 5.6 - Prob. 6TE Ch. 5.6 - Prob. 7TE Ch. 5.6 - Prob. 8TE Ch. 5 - Prob. 1CRQ Ch. 5 - Prob. 2CRQ Ch. 5 - Prob. 3CRQ Ch. 5 - Prob. 4CRQ Ch. 5 - Prob. 5CRQ Ch. 5 - Prob. 6CRQ Ch. 5 - Prob. 7CRQ Ch. 5 - Prob. 8CRQ Ch. 5 - Prob. 9CRQ Ch. 5 - Prob. 10CRQ Ch. 5 - Prob. 1RE Ch. 5 - Prob. 2RE Ch. 5 - Prob. 3RE Ch. 5 - Prob. 4RE Ch. 5 - Prob. 5RE Ch. 5 - Prob. 6RE Ch. 5 - Prob. 7RE Ch. 5 - Prob. 8RE Ch. 5 - 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The derivative of V ( n ) = C ( 1 − 2 N ) n .

Solution Summary: The author explains the derivative of V(n)=C (1-2N )n.

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The derivative of V(n)=C(1−2N)n.

The relative change of V(n)=C(1−2N)n.

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Chapter 5 Solutions