(a) Explanation Given Specific heat of the given rocks is 0.82 J/g-K . Temperature change is 12 ° C . Mass of the rocks is 50.0 kg ( 50.0 × 10 3 g ) . Formula The quantity of heat absorbed is calculated using the formula, q = C s × m × Δ T Where, q is the quantity of heat absorbed. C s is the specific heat (b) Interpretation Introduction To determine: The temperature change corresponding to the emission of 450 kJ of heat.

Test Prep Series for AP Chemistry for Chemistry: The Central Science 14th ed AP

14th Edition

ISBN: 9780134661483

Author: Edward L Waterman

Publisher: PEARSON

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Question

Chapter 5.5, Problem 5.5.2PE

(a)

Interpretation Introduction

To determine: The quantity of heat absorbed by the given mass of rocks.

(b)

Interpretation Introduction

To determine: The temperature change corresponding to the emission of 450 kJ of heat.

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Chapter 5.5, Problem 5.5.1PE

Chapter 5.5, Problem 5.6.1PE

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Chapter 5 Solutions

Test Prep Series for AP Chemistry for Chemistry: The Central Science 14th ed AP

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