Explanation Given information: The x is a continuous random variable, P x ≥ 20 , μ = 22 , σ = 5 . Concept used: If a random variable x follows normal distribution with mean μ and variance σ 2 , then x − μ σ follows a standard normal distribution with mean 0 and variance 1. Calculation: Convert P x ≥ 20 to standard normal. P x ≥ 20 = P z ≥ b − μ σ = P z ≥ 20 − 22 5 = P z ≥ − 2 5 = P z ≥ − 0.4 This P z ≥ − 0

Pearson eText Calculus and Its Applications, Brief Edition -- Instant Access (Pearson+)

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ISBN: 9780136880257

Author: Marvin Bittinger, David Ellenbogen

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Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 5.5, Problem 32E

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To calculate: The value of the Px≥20 .

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Chapter 5.5, Problem 31E

Chapter 5.5, Problem 33E

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Pearson eText Calculus and Its Applications, Brief Edition -- Instant Access (Pearson+)

Ch. 5.1 - In Exercises 1-14, is the price, in dollars per...Ch. 5.1 - In Exercises 1-14, is the price, in dollars per...Ch. 5.1 - In Exercises 1-14, D(x) is the price, in dollars...Ch. 5.1 - In Exercises 1-14, is the price, in dollars per...Ch. 5.1 - In Exercises 1-14, D(x) is the price, in dollars...Ch. 5.1 - In Exercises 1-14, D(x) is the price, in dollars...Ch. 5.1 - In Exercises 1-14, D(x) is the price, in dollars...Ch. 5.1 - Prob. 8E Ch. 5.1 - Prob. 9E Ch. 5.1 - Prob. 10E

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The value of the P x ≥ 20 .

Solution Summary: The author calculates the value of P(xge 20), which is a continuous random variable.

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