Explanation Given information: The x is a continuous random variable with standard normal distribution and P 0.76 ≤ x ≤ 1.45 . Calculation: The area bounded by the standard normal curve and the lines x = 0.76 and x = 1.45 is represented by P 0.76 ≤ x ≤ 1.45 . This P 0.76 ≤ x ≤ 1.45 can also be written as, P 0.76 ≤ x ≤ 1.45 = P 0 ≤ x ≤ 1.45 − P 0 ≤ x ≤ 0.76 . First, find P 0 ≤ x ≤ 1.45 . To find the required probability using the standard normal distribution, go down the left column to the value 1.4 , then in that row, move towards the right to the column headed 0.05. Note the value mentioned there. Thus, P 0 ≤ x ≤ 1.45 = 0.4265

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Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 5.5, Problem 17E

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To calculate: The value of P0.76≤x≤1.45 .

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Chapter 5.5, Problem 18E

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The value of P 0.76 ≤ x ≤ 1.45 .

Solution Summary: The author calculates the value of x, which is a continuous random variable with standard normal distribution.

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To calculate: The value of P0.76≤x≤1.45 .

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