Chapter 5.4, Problem 5.12AFP

Interpretation Introduction

Interpretation:

The volume of hydrogen chlroide gas formed at STP when $0.0117\text{kg}$ of sodium chloride reacts with sulphuric acid is to be calculated.

Concept introduction:

When the number of each atom in reactant side is equal to number of each atom in product side then the reaction is known as balanced chemical reaction.

The formula to calculate no. of moles is as follows:

$n=\frac{\text{weight}\left(m\right)}{\text{molecular}\text{weight}\left(M\right)}$ (1)

Volume of liquid at STP is $22.4\text{L}$.

Number of moles and volume at STP is related by the equation as follows:

$n=\frac{V}{V_{\text{STP}}}$                                                                                                                      (2)

Here, $V$ is the volume of liquid and $V_{\text{STP}}$ is the volume of liquid at STP.

Conversion factor to convert $\text{kg}$ into $\text{g}$ is as follows:

$1\text{kg}\text{=}{\text{10}}^3\text{g}$

Conversion factor to convert $\text{L}$ into $\text{mL}$ is as follows:

${10}^{-3}\text{L}=\text{1}\text{mL}$