Explanation Given information: The given Ebbinghaus model is f t = 85 e − 0.5 t + 15 , t ≥ 0 , where f t represents the percentage of the material that the student can recall t weeks later Graph: Substitute 0 for t in the equation f t = 85 e − 0.5 t + 15 , t ≥ 0 and simplify to calculate the value of f 0 f 0 = 85 e − 0.5 0 + 15 f 0 = 100 Substitute 1 for t in the equation f t = 85 e − 0.5 t + 15 , t ≥ 0 and simplify to calculate the value of f 1 f 1 = 85 e − 0.5 1 + 15 f 1 = 66.555 Substitute 2 for t in the equation f t = 85 e − 0.5 t + 15 , t ≥ 0 and simplify to calculate the value of f 2 f 2 = 85 e − 0.5 2 + 15 f 2 = 46.27 Substitute 3 for t in the equation f t = 85 e − 0.5 t + 15 , t ≥ 0 and simplify to calculate the value of f 3 f 3 = 85 e − 0

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ISBN: 9780137638826

Author: Goldstein

Publisher: PEARSON

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Chapter 5.4, Problem 36E

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To sketch: The graph of the Ebbinghaus model for ft=85e−0.5t+15 , t≥0

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Chapter 5.4, Problem 35E

Chapter 5.4, Problem 37E

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The graph of the Ebbinghaus model for f t = 85 e − 0.5 t + 15 , t ≥ 0

Solution Summary: The author illustrates the Ebbinghaus model, where f(t) represents the percentage of the material that the student can recall

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To sketch: The graph of the Ebbinghaus model for ft=85e−0.5t+15 , t≥0

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Chapter 5 Solutions