Big Ideas Math A Bridge To Success Algebra 2: Student Edition 2015
Big Ideas Math A Bridge To Success Algebra 2: Student Edition 2015
1st Edition
ISBN: 9781680331165
Author: HOUGHTON MIFFLIN HARCOURT
Publisher: Houghton Mifflin Harcourt
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Equations and Inequations
Equations and inequalities describe the relationship between two mathematical expressions.
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A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
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Chapter 5.4, Problem 33E
To determine

To solve : the given equation.

Expert Solution & Answer
Check Mark

Answer to Problem 33E

The solution of the given equation is x=5 .

Explanation of Solution

Given information :

The given equation:

  2(x+11)12=x+3

Concept used :

Solving equations with rational exponent:

  1. Isolate the power.
  2. Raise each side of the equation to the reciprocal of the rotational exponent.

Calculation :

As per problem,

    2 (x+11) 1 2 =x+3             [Write original equation]( 2(x+11)12)2=(x +3)2        [Square each side]         4(x+11)= x2+6x+9     [Expand the  right side and simplify the left side]           4x+44= x2+6x+9     [Multiply the left side]                    0=x2+2x−35       [Write in standard form]                    0=(x−5)(x+7)    [Factor]               x−5=0 or x+7=0   [Zero-Product property]                    x=5 or x=−7      [Solve for x]

To check the solution, substitute the values of x in the original equation

For x=5

   2 (5+11) 1 2 = ? 5+3   [Substitute x=5]          2(4)=?8     [Simplify]               8=8     

For x=−7

   2 (−7+11) 1 2 = ? −7+3   [Substitute x=−7]            2(2)=?−4        [Simplify]                 4≠−4     

Hence, the apparent solution x=−7 is extraneous. So, the only solution of the equation is x=5 .

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Chapter 5.4, Problem 32E
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Chapter 5.4, Problem 34E

Chapter 5 Solutions

Big Ideas Math A Bridge To Success Algebra 2: Student Edition 2015

Ch. 5.1 - Prob. 1ECh. 5.1 - Prob. 2ECh. 5.1 - Prob. 3ECh. 5.1 - Prob. 4ECh. 5.1 - Prob. 5ECh. 5.1 - Prob. 6ECh. 5.1 - Prob. 7ECh. 5.1 - Prob. 8ECh. 5.1 - Prob. 9ECh. 5.1 - Prob. 10E
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Prob. 59ECh. 5.2 - Prob. 60ECh. 5.2 - Prob. 61ECh. 5.2 - Prob. 62ECh. 5.2 - Prob. 63ECh. 5.2 - Prob. 64ECh. 5.2 - Prob. 65ECh. 5.2 - Prob. 66ECh. 5.2 - Prob. 67ECh. 5.2 - Prob. 68ECh. 5.2 - Prob. 69ECh. 5.2 - Prob. 70ECh. 5.2 - Prob. 71ECh. 5.2 - Prob. 72ECh. 5.2 - Prob. 73ECh. 5.2 - Prob. 74ECh. 5.2 - Prob. 75ECh. 5.2 - Prob. 76ECh. 5.2 - Prob. 77ECh. 5.2 - Prob. 78ECh. 5.2 - Prob. 79ECh. 5.2 - Prob. 80ECh. 5.2 - Prob. 81ECh. 5.2 - Prob. 82ECh. 5.2 - Prob. 83ECh. 5.2 - Prob. 84ECh. 5.2 - Prob. 85ECh. 5.2 - Prob. 86ECh. 5.2 - Prob. 87ECh. 5.2 - Prob. 88ECh. 5.3 - Prob. 1ECh. 5.3 - Prob. 2ECh. 5.3 - Prob. 3ECh. 5.3 - Prob. 4ECh. 5.3 - Prob. 5ECh. 5.3 - Prob. 6ECh. 5.3 - Prob. 7ECh. 5.3 - Prob. 8ECh. 5.3 - Prob. 9ECh. 5.3 - Prob. 10ECh. 5.3 - Prob. 11ECh. 5.3 - Prob. 12ECh. 5.3 - Prob. 13ECh. 5.3 - Prob. 14ECh. 5.3 - Prob. 15ECh. 5.3 - Prob. 16ECh. 5.3 - Prob. 17ECh. 5.3 - Prob. 18ECh. 5.3 - Prob. 19ECh. 5.3 - Prob. 20ECh. 5.3 - Prob. 21ECh. 5.3 - Prob. 22ECh. 5.3 - Prob. 23ECh. 5.3 - Prob. 24ECh. 5.3 - 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