BIG IDEAS MATH Algebra 1: Common Core Student Edition 2015
1st Edition
ISBN: 9781608408382
Author: HOUGHTON MIFFLIN HARCOURT
Publisher: Houghton Mifflin Harcourt
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Question
Chapter 5.4, Problem 22E
To determine
To find: The number of solutions of the system of linear equations
Expert Solution & Answer
Answer to Problem 22E
The system of linear equations
Explanation of Solution
Concept used:
The slope intercept formis
Here,
The condition of infinitely many solution: If the two linear equations has same slope and also has same y-intercept then the two equations has infinite many solutions.
The condition of no solution: If the two linear equations has same slope but has no same y -intercept then the two equations has no solution.
The condition of one solution: If the two linear equations has different slope but has either the same y -intercept or different y -intercept then the two equations has one solution.
Given information:
The system of linear equations is as follows:
Calculation:
The given system of linear equations is as follows:
Transform equation (1) in the form of slope intercept form.
Compare the obtained equation with general slope intercepts form to obtain the slope and y -intercept of the equation (1).
Transform equation (2) in the form of slope intercept form.
Compare the obtained equation to the general slope intercepts form to obtain the slope and y-intercept of the equation (2).
Therefore, the slope of equation (1) and equation (2) is different that is
It means equation (1) and equation (2) is represent the intersecting lines on the graph.
Therefore, it can be concluded that the given system of linear equation has one solution.
Conclusion:
Thus, the system of linear equations
Chapter 5 Solutions
BIG IDEAS MATH Algebra 1: Common Core Student Edition 2015
Ch. 5.1 - Prob. 1ECh. 5.1 - Prob. 2ECh. 5.1 - Prob. 3ECh. 5.1 - Prob. 4ECh. 5.1 - Prob. 5ECh. 5.1 - Prob. 6ECh. 5.1 - Prob. 7ECh. 5.1 - Prob. 8ECh. 5.1 - Prob. 9ECh. 5.1 - Prob. 10E
Ch. 5.1 - Prob. 11ECh. 5.1 - Prob. 12ECh. 5.1 - Prob. 13ECh. 5.1 - Prob. 14ECh. 5.1 - Prob. 15ECh. 5.1 - Prob. 16ECh. 5.1 - Prob. 17ECh. 5.1 - Prob. 18ECh. 5.1 - Prob. 19ECh. 5.1 - Prob. 20ECh. 5.1 - Prob. 21ECh. 5.1 - Prob. 22ECh. 5.1 - Prob. 23ECh. 5.1 - Prob. 24ECh. 5.1 - Prob. 25ECh. 5.1 - Prob. 26ECh. 5.1 - Prob. 27ECh. 5.1 - Prob. 28ECh. 5.1 - Prob. 29ECh. 5.1 - Prob. 30ECh. 5.1 - Prob. 31ECh. 5.1 - Prob. 32ECh. 5.1 - Prob. 33ECh. 5.1 - Prob. 34ECh. 5.1 - Prob. 35ECh. 5.1 - Prob. 36ECh. 5.2 - Prob. 1ECh. 5.2 - Prob. 2ECh. 5.2 - Prob. 3ECh. 5.2 - Prob. 4ECh. 5.2 - Prob. 5ECh. 5.2 - Prob. 6ECh. 5.2 - Prob. 7ECh. 5.2 - Prob. 8ECh. 5.2 - Prob. 9ECh. 5.2 - Prob. 10ECh. 5.2 - Prob. 11ECh. 5.2 - Prob. 12ECh. 5.2 - Prob. 13ECh. 5.2 - Prob. 14ECh. 5.2 - Prob. 15ECh. 5.2 - Prob. 16ECh. 5.2 - Prob. 17ECh. 5.2 - Prob. 18ECh. 5.2 - Prob. 19ECh. 5.2 - Prob. 20ECh. 5.2 - Prob. 21ECh. 5.2 - Prob. 22ECh. 5.2 - Prob. 23ECh. 5.2 - Prob. 24ECh. 5.2 - Prob. 25ECh. 5.2 - Prob. 26ECh. 5.2 - Prob. 27ECh. 5.2 - 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