Biology
5th Edition
ISBN: 9781260487947
Author: BROOKER
Publisher: MCG
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Chapter 53.3, Problem 1CS
Core Skill: Modeling The goal of this modeling challenge is to make a model that depicts the relative movement of fluid between a capillary and the interstitial fluid when the amount of protein in an animal's blood is abnormally low.
Model of fluid movement into and out of a capillary
Modeling Challenge: In the simplified model of fluid movement between a capillary and interstitial fluid on the right, two sets of arrows are used to indicate the net movement of fluid at two places along a capillary: near the arteriole and near the venule. The length of an arrow represents the relative amount of fluid moving from one compartment to the other. Let’s assume that the protein concentration of the blood becomes lower than normal (this could happen, for example, in a malnourished animal). Draw a model like the one given with arrows showing the relative fluid movements at the arterial and venule ends of the capillary under these new conditions. Remember to use the length of an arrow to indicate the relative amount of fluid movement; a longer arrow represents a greater amount of fluid moving into or out of the capillary.
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QUESTION 3
The table below shows the results of an investigation in which the effect of
temperature and light on the yield of tomatoes in two greenhouses on a farm
was investigated.
TEMPERATURE
(°C)
AVERAGE YIELD OF TOMATOES PER
3.1
PLANT
(kg)
LOW LIGHT LEVELS
HIGH LIGHT LEVELS
5
0,5
0,5
10
1,5
2,5
15
3,0
5,0
20
3,6
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3,5
7,8
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2,5
6,2
State TWO steps the investigator may have taken into
consideration during the planning stage of the investigation.
(2)
3.2
Identify the:
a) Independent variables
(2)
b) Dependent variable
(1)
3.3
Plot a line graph showing the results of the average yield of the
tomatoes from 5°C to 30°C for low light levels.
(6)
3.4
State ONE way in which the scientists could have improved the…
Explain why you chose this mutation. Begin by transcribing and translating BOTH the
normal and abnormal DNA sequences. The genetic code below is for your reference.
SECOND BASE OF CODON
כ
FIRST BASE OF CODON
O
THIRD BASE OF CODON
SCAGUCAGUGAGUCAG
UUU
UUC
UCU
UAU
UGU
Phenylalanine
(F)
Tyrosine (Y)
Cysteine (C)
UCC
UAC
UGC
Serine (S)
UUA
UUG
Leucine (L)
UCA
UCG_
UAA
UGA
Stop codon
-Stop codon
UAG
UGG -Tryptophan (W)
CUU
CUC
CCU
CAU
CGU
Histidine (H)
CCC
CAC
CGC
-Leucine (L)
Proline (P)
CUA
CCA
CAA
CUG
CCG
CAG-Glutamine (Q)
-Arginine (R)
CGA
CGG
AUU
ACU
AAU
AGU
AUC
Isoleucine (1)
Asparagine (N)
ACC
AAC
Threonine (T)
AUA
ACA
AAA
Methionine (M)
Lysine (K)
AUG
ACG
Start codon
AAG
AGC-Serine (S)
-Arginine (R)
AGA
AGG
GUU
GCU
GAU
GUC
GUA
GUG
GCC
Valine (V)
-Alanine (A)
GCA
GCG
GAC
GAA
GAG
Aspartic acid
(D)
GGU
Glutamic acid
(E)
GGC
GGA
GGG
Glycine (G)
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Chapter 53 Solutions
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