Mechanics of Materials
9th Edition
ISBN: 9780133254426
Author: Russell C. Hibbeler
Publisher: Prentice Hall
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 5.3, Problem 5.46P
A motor delivers 500 hp to the shaft, which is tubular and has an outer diameter of 2 in. If it is rotating at 200 rad/s, determine its largest inner diameter to the nearest
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
!
Required information
A one-shell-pass and eight-tube-passes heat exchanger is used to heat glycerin (cp=0.60 Btu/lbm.°F) from 80°F to 140°F
by hot water (Cp = 1.0 Btu/lbm-°F) that enters the thin-walled 0.5-in-diameter tubes at 175°F and leaves at 120°F. The total
length of the tubes in the heat exchanger is 400 ft. The convection heat transfer coefficient is 4 Btu/h-ft²°F on the glycerin
(shell) side and 70 Btu/h-ft²°F on the water (tube) side.
NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.
Determine the rate of heat transfer in the heat exchanger before any fouling occurs.
Correction factor F
1.0
10
0.9
0.8
R=4.0 3.0 2.0.15 1.0 0.8.0.6 0.4 0.2
0.7
0.6
R=
T1-T2
12-11
0.5
12-11
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0
(a) One-shell pass and 2, 4, 6, etc. (any multiple of 2), tube passes
P=
T₁-11
The rate of heat transfer in the heat exchanger is
Btu/h.
!
Required information
Air at 25°C (cp=1006 J/kg.K) is to be heated to 58°C by hot oil at 80°C (cp = 2150 J/kg.K) in a cross-flow heat exchanger
with air mixed and oil unmixed. The product of heat transfer surface area and the overall heat transfer coefficient is 750
W/K and the mass flow rate of air is twice that of oil.
NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.
Air
Oil
80°C
Determine the effectiveness of the heat exchanger.
In an industrial facility, a counter-flow double-pipe heat exchanger uses superheated steam at a temperature of 155°C to
heat feed water at 30°C. The superheated steam experiences a temperature drop of 70°C as it exits the heat exchanger.
The water to be heated flows through the heat exchanger tube of negligible thickness at a constant rate of 3.47 kg/s. The
convective heat transfer coefficient on the superheated steam and water side is 850 W/m²K and 1250 W/m²K,
respectively. To account for the fouling due to chemical impurities that might be present in the feed water, assume
a fouling factor of 0.00015 m²-K/W for the water side.
The specific heat of water is determined at an average temperature of (30 +70)°C/2 = 50°C and is taken to be
J/kg.K.
Cp=
4181
Water
Steam
What would be the required heat exchanger area in case of parallel-flow arrangement?
The required heat exchanger area in case of parallel-flow arrangement is
1m².
Chapter 5 Solutions
Mechanics of Materials
Ch. 5.3 - Determine the internal torque at each section and...Ch. 5.3 - Determine the. internal torque at each section and...Ch. 5.3 - The solid and hollow shafts are each subjected to...Ch. 5.3 - The motor delivers 10 hp to the shaft. If it...Ch. 5.3 - The solid circular shaft is subjected to an...Ch. 5.3 - The hollow circular shaft is subjected to an...Ch. 5.3 - The shaft is hollow from A to B and solid from B...Ch. 5.3 - Determine the maximum shear stress in the...Ch. 5.3 - Determine the maximum shear stress in the shaft at...Ch. 5.3 - Determine the shear stress a: point A on the...
Ch. 5.3 - The solid 50-mm-diameter shaft is subjected to the...Ch. 5.3 - The gear motor can develop 3 hp when it turns at...Ch. 5.3 - The solid shaft of radius r is subjected to a...Ch. 5.3 - The solid shaft of radius r is subjected to a...Ch. 5.3 - 5-3. The solid shaft is fixed to the support at C...Ch. 5.3 - The copper pipe has an outer diameter of 40 mm and...Ch. 5.3 - The copper pipe has an outer diameter of 2.50 in....Ch. 5.3 - Prob. 5.6PCh. 5.3 - Prob. 5.7PCh. 5.3 - The solid 30-mm-diameter shaft is used to transmit...Ch. 5.3 - The solid shaft is fixed to the support at C and...Ch. 5.3 - Prob. 5.10PCh. 5.3 - The assembly consists of two sections of...Ch. 5.3 - Prob. 5.12PCh. 5.3 - 5-13. If The tubular shaft is made from material...Ch. 5.3 - A steel tube having an outer diameter of 2.5 in....Ch. 5.3 - Prob. 5.15PCh. 5.3 - Prob. 5.16PCh. 5.3 - The rod has a diameter of 1 in. and a weight of 10...Ch. 5.3 - The rod has a diameter of 1 in. and a weight of 15...Ch. 5.3 - 5-19. The shaft consists of solid 80-mm-diameter...Ch. 5.3 - Prob. 5.20PCh. 5.3 - 5-21. If the 40-mm-diameter rod is subjected to a...Ch. 5.3 - Prob. 5.22PCh. 5.3 - Prob. 5.23PCh. 5.3 - Prob. 5.24PCh. 5.3 - Prob. 5.25PCh. 5.3 - Prob. 5.26PCh. 5.3 - Prob. 5.27PCh. 5.3 - Prob. 5.28PCh. 5.3 - Prob. 5.29PCh. 5.3 - Prob. 5.30PCh. 5.3 - The solid steel shaft AC has a diameter of 25 mm...Ch. 5.3 - The pump operates using the motor that has a power...Ch. 5.3 - Prob. 5.33PCh. 5.3 - Prob. 5.34PCh. 5.3 - Prob. 5.35PCh. 5.3 - Prob. 5.36PCh. 5.3 - Prob. 5.37PCh. 5.3 - Prob. 5.38PCh. 5.3 - Prob. 5.39PCh. 5.3 - Prob. 5.40PCh. 5.3 - The A-36 steel tubular shaft is 2 m long and has...Ch. 5.3 - Prob. 5.42PCh. 5.3 - The solid shaft has a linear taper from rA at one...Ch. 5.3 - *5-44. The rod has a diameter of 0.5 in. and...Ch. 5.3 - 5-45. Solve Prob. 5-44 for the maximum torsional...Ch. 5.3 - A motor delivers 500 hp to the shaft, which is...Ch. 5.4 - The 60 mm-diameter steel shaft is subjected to the...Ch. 5.4 - Prob. 5.10FPCh. 5.4 - The hollow 6061-T6 aluminum shaft has an outer and...Ch. 5.4 - A series of gears are mounted on the...Ch. 5.4 - The 80-mm-diameter shaft is made of steel. If it...Ch. 5.4 - The 80-mm-diameter shaft is made of steel. If it...Ch. 5.4 - The propellers of a ship are connected to an A-36...Ch. 5.4 - Show that the maximum shear strain in the shaft is...Ch. 5.4 - 5-49. The A-36 steel axle is made from tubes AB...Ch. 5.4 - Prob. 5.50PCh. 5.4 - Determine the maximum allowable torque T. Also,...Ch. 5.4 - If the allowable shear stress is allow = 80 MPa,...Ch. 5.4 - Prob. 5.53PCh. 5.4 - If gear B supplies 15 kW of power, while gears A,...Ch. 5.4 - If the shaft is made of steel with the allowable...Ch. 5.4 - *5-56. The A-36 steel axle is made from tubes AB...Ch. 5.4 - If the rotation of the 100-mm-diameter A-36 steel...Ch. 5.4 - If the rotation of the 100-mm-diameter A-36 steel...Ch. 5.4 - It has a diameter of 1 in. and is supported by...Ch. 5.4 - Prob. 5.60PCh. 5.4 - Prob. 5.61PCh. 5.4 - Prob. 5.62PCh. 5.4 - Prob. 5.63PCh. 5.4 - Prob. 5.64PCh. 5.4 - Prob. 5.65PCh. 5.4 - When it is rotating at 80 rad/s. it transmits 32...Ch. 5.4 - It is required to transmit 35 kW of power from the...Ch. 5.4 - Prob. 5.68PCh. 5.4 - If a torque of T = 50 N m is applied to the bolt...Ch. 5.4 - If a torque of T= 50N m is applied to the bolt...Ch. 5.4 - Prob. 5.72PCh. 5.4 - If the shaft is subjected to a torque T at its...Ch. 5.4 - Prob. 5.74PCh. 5.4 - Prob. 5.75PCh. 5.4 - *5-76. A cylindrical spring consists of a rubber...Ch. 5.5 - Gst = 75 GPa.Ch. 5.5 - The A992 steel shaft has a diameter of 60 mm and...Ch. 5.5 - If the shaft is fixed at its ends A and B and...Ch. 5.5 - Prob. 5.80PCh. 5.5 - Prob. 5.81PCh. 5.5 - 5-82. The shaft is made from a solid steel section...Ch. 5.5 - 5-83. The motor A develops a torque at gear B of...Ch. 5.5 - If the allowable shear stresses for the magnesium...Ch. 5.5 - If a torque of T = 5 kNm is applied to end A,...Ch. 5.5 - Each has a diameter of 25 mm and they are...Ch. 5.5 - Each has a diameter of 25 mm and they are...Ch. 5.5 - It is fixed at its ends and subjected to a torque...Ch. 5.5 - 5–89. Determine the absolute maximum shear stress...Ch. 5.5 - The shaft is subjected to a torque of 800 lbft....Ch. 5.5 - Prob. 5.91PCh. 5.5 - The shaft is made of 2014-T6 aluminum alloy and is...Ch. 5.5 - The tapered shaft is confined by the fixed...Ch. 5.5 - Determine the reactions at the fixed supports A...Ch. 5.7 - 5-95. The aluminum rod has a square cross section...Ch. 5.7 - Prob. 5.96PCh. 5.7 - Prob. 5.97PCh. 5.7 - If it is subjected to the torsional loading,...Ch. 5.7 - Solve Prob.5-98 for the maximum shear stress...Ch. 5.7 - determine the maximum shear stress in the shaft....Ch. 5.7 - If the shaft has an equilateral triangle cross...Ch. 5.7 - 5-102. The aluminum strut is fixed between the two...Ch. 5.7 - is applied to the tube If the wall thickness is...Ch. 5.7 - If it is 2 m long, determine the maximum shear...Ch. 5.7 - Also, find the angle of twist of end B. The shaft...Ch. 5.7 - Also, find the corresponding angle of twist at end...Ch. 5.7 - If the solid shaft is made from red brass C83400...Ch. 5.7 - If the solid shaft is made from red brass C83400...Ch. 5.7 - The tube is 0.1 in. thick.Ch. 5.7 - 5-110. For a given maximum average shear stress,...Ch. 5.7 - 5-111. A torque T is applied to two tubes having...Ch. 5.7 - By what percentage is the torsional strength...Ch. 5.7 - 5-113. Determine the constant thickness of the...Ch. 5.7 - 5-114. Determine the torque T that can be applied...Ch. 5.7 - If the allowable shear stress is allow = 8 ksi,...Ch. 5.7 - *5-116. The tube is made of plastic, is 5 mm...Ch. 5.7 - 5–117. The mean dimensions of the cross section of...Ch. 5.7 - 5–118. The mean dimensions of the cross section of...Ch. 5.7 - If it is subjected to a torque of T = 40 Nm....Ch. 5.10 - If the transition between the cross sections has a...Ch. 5.10 - 5–121. The step shaft is to be designed to rotate...Ch. 5.10 - Prob. 5.122PCh. 5.10 - 5–123. The transition at the cross sections of the...Ch. 5.10 - *5–124. The steel used for the step shaft has an...Ch. 5.10 - 5–125. The step shaft is subjected to a torque of...Ch. 5.10 - Determine the radius of the elastic core produced...Ch. 5.10 - Assume that the material becomes fully plastic.Ch. 5.10 - diameter is subjected to a torque of 100 in.kip....Ch. 5.10 - Determine the torque T needed to form an elastic...Ch. 5.10 - Determine the torque applied to the shaft.Ch. 5.10 - 5–131. An 80-mm-diameter solid circular shaft is...Ch. 5.10 - Determine the ratio of the plastic torque Tp to...Ch. 5.10 - 5–133. If the step shaft is elastic-plastic as...Ch. 5.10 - 5–134. The solid shaft is made from an...Ch. 5.10 - 5–135. A 1.5-in.-diameter shaft is made from an...Ch. 5.10 - *5–136. The tubular shaft is made of a...Ch. 5.10 - 5–137. The shaft is made from a strain-hardening...Ch. 5.10 - 5–138. The tube is made of elastic-perfectly...Ch. 5.10 - Determine the torque required to cause a maximum...Ch. 5.10 - *5–140. The 2-m-long tube is made of an...Ch. 5.10 - is made from an elastic perfectly plastic material...Ch. 5.10 - 5–142. The 2-m-long lube is made from an...Ch. 5 - The shaft is made of A992 steel and has an...Ch. 5 - The shaft is made of A992 steel and has an...Ch. 5 - Determine the shear stress at the mean radius p =...Ch. 5 - If the thickness of its 2014-T6-aluminum skin is...Ch. 5 - Determine which shaft geometry will resist the...Ch. 5 - If couple forces P = 3 kip are applied to the...Ch. 5 - If the allowable shear stress for the aluminum is...Ch. 5 - Determine the angle of twist of its end A if it is...Ch. 5 - This motion is caused by the unequal belt tensions...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- A single-pass crossflow heat exchanger is used to cool jacket water (cp = 1.0 Btu/lbm.°F) of a diesel engine from 190°F to 140°F, using air (Cp = 0.245 Btu/lbm.°F) at inlet temperature of 90°F. Both air flow and water flow are unmixed. If the water and air mass flow rates are 85500 lbm/h and 400,000 lbm/h, respectively, determine the log mean temperature difference for this heat exchanger. Assume the correction factor F to be 0.92. Air flow (unmixed) Water flow (unmixed) The log mean temperature difference of the heat exchanger is °F.arrow_forwardusing the theorem of three moments, find all the reactions and supports, I need concise calculations only. the answers are at the bottom, I need concise steps and minimal explanationsarrow_forwardIn an industrial facility, a counter-flow double-pipe heat exchanger uses superheated steam at a temperature of 155°C to heat feed water at 30°C. The superheated steam experiences a temperature drop of 70°C as it exits the heat exchanger. The water to be heated flows through the heat exchanger tube of negligible thickness at a constant rate of 3.47 kg/s. The convective heat transfer coefficient on the superheated steam and water side is 850 W/m²K and 1250 W/m²K, respectively. To account for the fouling due to chemical impurities that might be present in the feed water, assume a fouling factor of 0.00015 m² K/W for the water side. The specific heat of water is determined at an average temperature of (30+70)°C/2 = 50°C and is taken to be Cp J/kg-K. Water Steam Determine the heat exchanger area required to maintain the exit temperature of the water to a minimum of 70°C. The heat exchanger area required isarrow_forward
- Stress, ksi 160 72 150- 140 80 70 ༄ ྃ ༈ ཎྜ རྦ ༅ ཎྜ ྣཧྨ ➢ 130 120 110 100 90 2.0 2.8 3.6 4.4 5 Wire diameter, mm 6.0 6.8 2 7.6 8.4 Compression and extension springs. ASTM A227 Class II Light service Average service 0.020 0.060 0.100 0.140 0.180 0.220 0.260 0.300 0.340 0.380 0.420 0.460 0.500 Wire diameter, in Torsional stress due to initial tension, ksi 10 ४ 20 Preferred range 100 Stress, MPa 9.2 10.0 10.8 11.6 12.4 1100 1035 965 895 825 760 Severe service 690 620 550 50 150 3456789 10 11 12 13 14 15 16 Spring index, C = DJD FIGURE 18-21 Recommended torsional shear stress in an extension spring due to initial tension (Data from Associated Spring, Barnes Group, Inc.) 50 200 485 Stress, MPaarrow_forwardBolted Joint Design Bolted Frames Total Force due to door weight: P = 240 lb Number of Bolts: N = Distance to Bolt C/L: a = 4 N/A Bolt Material - Allowable shear stress of bolt material: T₂ = x Distance from Bolt centroid to bolt: x = y Distance from Bolt centroid to bolt: y = Degrees per Radian- Results y-Load on each bolt: F, = Moment resisted by bolt pattern: M = Radial distance from Bolt centroid to bolt: r = Sum squares of all radial distances: Σr² Force on each bolt to resist moment: F, - Angle for force composition: e= X-Force on each bolt to resist moment: F- y-Force on each bolt to resist moment: Fly Total y-Force on each bolt: Fy = Resultant force on bolt 1: R₁ = Required shear stress area for a bolt: A₂ = ASTM Grade A307 Steel 10,000 0 psi from Table 20-1 3.0 57.296 in degrees lb per bolt lb-in Formula FS-P/N M-Px XB r = (x² + y²)0.5 in² Σ 4r² Mr F₁ = Στ lb degrees lb lb lb Minimum Bolt Diameter: Din = Rounded up Bolt Diameter: D = 55 P. 1.5 in 2 in (3x) 1 in This bracket…arrow_forwardUniversity of Babylon Collage of Engineering/ Al-Musayab Department of Automobiles Final Examination/ Stage: 3rd Notes: Answer 4 questions only 2023-2202 Subject: Theory of vehicles Date: 2023\06\10-Saturday Time: Three Hours Course 2nd Attempt 1st Q1: A Hooke's coupling connects two shafts whose axes are inclined at 30°. The of the driven shaft? Find the maximum value of retardation or acceleration and driving shaft rotates uniformly at 600 rpm. What are the extreme angular velocities state the angle where both will occur. (12.5 Marks) Q2: Four masses, A, B, C, and D), revolve at equal radii and are equally spaced along a shaft. The mass B is 7 kg, and the radius of C and D make angles of 90° and 240°, respectively, with the radius of B. Find the magnitude of the masses A, C, and D and the angular position of A so that the system may be completely balanced. (12.5 Marks) Q3: A cam has straight worked faces that are tangential to a base circle of diameter 90 mm. The follower is a roller…arrow_forward
- Problem 18-26 Added Extension Springs Spring Material ASTM A227 Modulus of Elasticity of the Material in Shear: G 1.150E+07 psi Average Service Max Operating Load: F₁ = 100 lb Max Length between attachment points: L₁ = 60.00 in 20.00 lb 26.00 1.400 Min Operating Load: F₁ = Min Length between attachment points: L₁ = Maximum Outside Diameter = in in Results Note: you select a wire diameter from the "US steel wire gage" column in table 18-2 Formula k = AF/AL k = (F0-F1)/(Lo - L₁) Spring Rate: k = lb/in Assumed Trial Outside Diameter: OD = Assumed Trial Mean: D ma Assumed Design Stress in Spring: Tda in 1.070 in 102,000 psi Assumed Wahl Factor: K = 1.2 Calculated Wire Diameter: Dwa Actual Wire Diameter: Dw Actual outer diameter: OD = Actual inner diameter: ID= Spring Index: C = See Figure 18-8 Dw= [8KF Dm πTd 1/3 in 5' 5' 5' 5' This corresponds to US Steel 9 wire gage ID = Dm - Dw C = Dm/Dw 4C - 1 0.615 K = + 4C - с Wahl Factor: K = 8KFDm 8KFC T = TD πD Stress in Spring at F = Fo: To psi…arrow_forwardCHAIN DRIVE DESIGN Initial Input Data: Application: Garage Door Opener Drive type: AC Motor Driven machine Chain and Sprocket to pull the door up Degrees per Radian: 57.2958 degrees Sprocket Diameter: D = 1.690 in Number of strands: Chain number: 1 40 Service factor: 1.3 Table 7-10 No. of teeth Computed Data: Actual Motor Power Input: 0.000 hp Sprocket Speed (for sprocket attached to gear shaft) Design power: 0.00 rpm 0 hp 11 12 0.06 0.15 0.29 0.56 0.99 1.09 1.61 2.64 TABLE 7-7 Horsepower Ratings-Single Strand Roller Chain No. 40 0.500 inch pitch 10 25 50 100 180 200 300 500 700 900 1000 1: 0.06 0.14 0.27 0.52 0.91 1.00 1.48 2.42 3.34 4.25 4.70 ! 3.64 4.64 5.13 13 0.07 0.16 0.31 0.61 1.07 1.19 1.75 2.86 3.95 5.02 5.56 Design Decisions-Chain Type and Teeth Numbers: 14 Chain number: Use Table 7-7 Chain pitch: p = in 15 Number of Teeth: N = Per Table 7-7 16 0.08 0.20 0.39 0.75 1.32 1.46 2.15 3.52 0.07 0.17 0.34 0.66 1.15 1.28 1.88 3.08 0.08 0.19 0.36 0.70 1.24 1.37 2.02 3.30 4.55 5.80…arrow_forwardInput Data: Torque needed to overcome rolling friction in rollers, slides and other moving parts, except for Motor and Worm Gear the worm gear T₁ = Length of travel of door: Time for door to open or close: LD = 50 lb-in. 90 in t= 12.5 seconds Pitch diameter for chain sprocket: DPC 1.690 in Weight of Door: P = No. of worm threads: Nw = Worm Pitch diameter: Dw Diametral pitch: Pd Normal pressure angle: Degrees per Radian: Number of gear teeth: Calculated Data: Linear velocity of door and chain (in/sec): Linear velocity of door and chain (ft/min): Output Speed of Gear and Sprocket: Upward Force due to Weight of Door: Фо = = NG= 240 lb 2 1.250 in 12 14.5 degrees 57.2958 degrees 28 Vα= in/sec VC= ft/min NG = rpm FD lb Net Upward Force on Door: Fou lb Torque on gear ignoring rolling friction: TG = lb-in. Formula = FDU FD-2 x Fo (note: Fo is the Max Operating load of the extension springs). This is also the initial tension in the chain. TG = FDU X DPC/2 This is the also the torque on the…arrow_forward
- Q5/A: A car with a track of 1.5 m and a wheelbase of 2.9 m has a steering gear mechanism of the Ackermann type. The distance between the front stub axle pivots is 1.3 m. The length of each track arm is 150 mm, and the length of the track rod is 1.2 m. Find the angle turned through by the outer wheel if the angle turned through by the inner wheel is 30°. (6 Marks) Q5/B: Write True on the correct sentences and False on the wrong sentences listed below:- 1- In automobiles, the power is transmitted from the gearbox to the differential through bevel gears. 2- The minimum radius circle drawn to the cam profile is called the base circle. 3- The Proell governor, compared to the Porter governor, has less lift at the same speed. 4- The balancing of rotating and reciprocating parts of an engine is necessary when it runs at a slow speed. (6.5 Marks) ***Best of Luck *** جامعة بابل UNIVERSITY OF BABYLON Examiner: Mohanad R. Hameed Head of Department: Dr. Dhyai H. Jawadarrow_forwardUniversity of Babylon Collage of Engineering/ Al-Musayab Department of Automobiles Mid Examination/ Stage: 3rd Subject: Theory of Vehicles Date: 14 \ 4 \2025 Time: 1.5 Hours 2025-2024 Q1: The arms of a Porter governor are 250 mm long. The upper arms are pivoted on the axis of revolution, but the lower arms are attached to a sleeve at a distance of 50 mm from the axis of rotation. The weight on the sleeve is 600 N and the weight of each ball is 80 N. Determine the equilibrium speed when the radius of rotation of the balls is 150 mm. If the friction is equivalent to a load of 25 N at the sleeve, determine the range of speed for this position. Q2: In a loaded Proell governor shown in Figure below each ball weighs 3 kg and the central sleeve weighs 25 kg. The arms are of 200 mm length and pivoted about axis displaced from the central axis of rotation by 38.5 mm, y=238 mm, x=303.5 mm, CE 85 mm, MD 142.5 mm. Determine the equilibrium speed. Fe mg E M 2 Q3: In a spring loaded Hartnell type…arrow_forwardusing the theorem of three moments, find all the reactions and supports, I need the calculations onlyarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University Press
Mechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSON
Thermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEY
Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Engineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
Power Transmission; Author: Terry Brown Mechanical Engineering;https://www.youtube.com/watch?v=YVm4LNVp1vA;License: Standard Youtube License