Explanation Given information: A function graph is given as below and ∫ 0 4 f ( x ) d x is smallest. Concept used: 1. Area under a function graph in the interval [ a , b ] gives the integral value ∫ a b f ( x ) d x . 2. Area above x − axis is counted positive and area below x − axis is counted negative. Calculation: A function graph is given as below. Since, area above x − axis is counted positive and area below x − axis is counted negative

6th Edition

ISBN: 9781119399322

Author: Hughes-Hallett

Publisher: WILEY

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Chapter 5.3, Problem 38P

To determine

The limit a and b in the interval [0,5] satisfying given condition.

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Chapter 5.3, Problem 37P

Chapter 5.3, Problem 39P

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3.1 Limits 1. If lim f(x)=-6 and lim f(x)=5, then lim f(x). Explain your choice. x+3° x+3* x+3 (a) Is 5 (c) Does not exist (b) is 6 (d) is infinite

1 pts Let F and G be vector fields such that ▼ × F(0, 0, 0) = (0.76, -9.78, 3.29), G(0, 0, 0) = (−3.99, 6.15, 2.94), and G is irrotational. Then sin(5V (F × G)) at (0, 0, 0) is Question 1 -0.246 0.072 -0.934 0.478 -0.914 -0.855 0.710 0.262 .

2. Answer the following questions. (A) [50%] Given the vector field F(x, y, z) = (x²y, e", yz²), verify the differential identity Vx (VF) V(V •F) - V²F (B) [50%] Remark. You are confined to use the differential identities. Let u and v be scalar fields, and F be a vector field given by F = (Vu) x (Vv) (i) Show that F is solenoidal (or incompressible). (ii) Show that G = (uvv – vVu) is a vector potential for F.

Chapter 5 Solutions

APPLIED CALCULUS (WILEY PLUS)

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The limit a and b in the interval [ 0 , 5 ] satisfying given condition.

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Chapter 5 Solutions