Electrical Motor Controls for Integrated Systems
5th Edition
ISBN: 9780826912268
Author: Gary Rockis;Glen A. Mazur
Publisher: American Technical Publishers
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Chapter 5.2, Problem 3CP
To determine
To provide: The name of the circuit control logic used in the decision section represented in Figure 5-7.
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Solve this. find the initial conditions ic(0-) and vc(0-) the switch opens at t=0 so it's closed at t=0- dont copy the response from previous because it's wrong. please solve in great detail explaining everything step by step. now the way i thought about it is Getting millman voltage (1/3)-2 / (1/3)+(1/2) and it's the same as Vc as both are nodal voltages but i wasn't sure if correct. because i didnt take into consideration all voltages (Vc here) even though it's the same so i'm quite confused. please explain to me if i'm correct and if not tell me why and where my thinking was flawed. thank you
3. Consider the RL circuit with a constant voltage source shown in the diagram below. The
values of the resistor, inductor, and input voltage are R = 100, L = 100 mH, and Vo = 12V,
respectively.
Vo
-
Ti(t)
R
w
When the switch closes at time t = 0, the current begins to flow as a function of time. It
follows from Kirchoff's voltage law that the current is described by the differential equation
di(t)
L
dt
+ Ri(t) = Vo⋅
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Electrical Motor Controls for Integrated Systems
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- 4. Consider the RL circuit with a sinusoid voltage source shown in the diagram below. The values of the resistor, inductor, input voltage amplitude and frequency are R = 5, L = 50mH, and Vo = 10 V, respectively. The input voltage frequency w is variable. Assume that the circuit has reached steady state. Voejwt + ↑i(t) R سيد The input voltage can be described using the complex sinusoid function V(t) = Voejwt The current is given by a sinusoid with same the frequency was the input voltage, but a different magnitude and different phase. The physical voltage and current are obtained by taking the real part. In complex form, the current is given by i(t) Vo ejwt R1+jw/ The differential equation that describes the current follows from Kirchoff's voltage law, and is given by di(t) L + Ri(t) = Voejwt dtarrow_forward2. (4 marks) Use the real and imaginary parts of ĉejut, where ñ = a + jb = e³, to show that: c cos(wt) = acos(wt) – bsin(wt), csin(wt) = a sin(wt) + bcos(wt). Describe the relations between a, b, c, and o.arrow_forwardCompute the thevenin equivalent between the two terminals a-b zeq and veq show all your steps and explain clearly what you did.arrow_forward
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- conpute the thevenin equivalent between the terminals a and b Veq and Zeq note that the voltage source has 5e^j0 V the other values if not clear are -8j 8 20 and 5ohmsarrow_forward-calculate theoretical voltage and current values in Figure 1.3 and record them in Table 1.1. Calculate-all- voltage and current values as peak-to-peak. Table 1.1: Calculated Values of RC-Circuit ZTotale in (p-to-p)¤ VR-(p-to-p)¤ Vc-(p-to-p)¤ R(2) X-(2) mag (mA) angled mag (V) angled mag-(V) angle Freq. (Hz) X (N)- ρα ρα 500x 4000x ρα ρα ρα ρα ρα ρα ρα ραarrow_forwardQ1 .Determine the model of the following system using Mason's rulearrow_forward
- A three-phase delta-connected load, each phase of which has an inductive reactance of 40 Ω and a resistance of 25 Ω, is fed from the secondary of a three-phase star-connected transformer which has a phase voltage of 230 V. Draw the circuit diagram of the system and calculate: (a) the current in each phase of the load; (b) the p.d. across each phase of the load; (c) the current in the transformer secondary windings; (d) the total active power taken from the supply and its power factor. ANS= 8.8 A, 416 V, 15.25 A, 5810 Warrow_forward"I need something clear written by hand with steps." Find Laplace transform and the corresponding ROC for x(t) = e−3sin(2t) u(t)dtarrow_forwardThree similar coils, connected in star, take a total power of 1.5 kW, at a power factor of 0.2, from a three-phase, 400 V, 50 Hz supply. Calculate: (a) the resistance and inductance of each coil; (b) the line currents if one of the coils is short-circuited.arrow_forward
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