Explanation Here we can see that since function which is given to integration are the same in both cases. The only difference is we are integrating with different variable but still the value definite limit and function are same so the required answer will also be the same. Thus, ∫ 0 2 e

Applied Calculus, 6e WileyPLUS + Loose-leaf

6th Edition

ISBN: 9781119408901

Author: Deborah Hughes-Hallett, Andrew M. Gleason, Patti Frazer Lock, Daniel E. Flath

Publisher: Wiley (WileyPLUS Products)

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Chapter 5.2, Problem 25P

To determine

Without calculation, explain about the relationship between the values of the two integrals: ∫02ex2dx and ∫02et2dt.

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Chapter 5.2, Problem 24P

Chapter 5.2, Problem 26P

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Applied Calculus, 6e WileyPLUS + Loose-leaf

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Without calculation, explain about the relationship between the values of the two integrals: ∫ 0 2 e x 2 d x and ∫ 0 2 e t 2 d t .

Solution Summary: The author explains the relationship between the values of the two integrals without calculation. Since function which is given to integration are the same in both cases.

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Without calculation, explain about the relationship between the values of the two integrals: ∫02ex2dx and ∫02et2dt.

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Chapter 5 Solutions