EBK MATHEMATICS FOR MACHINE TECHNOLOGY
8th Edition
ISBN: 9781337798396
Author: SMITH
Publisher: CENGAGE LEARNING - CONSIGNMENT
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Textbook Question
Chapter 52, Problem 1A
What is the complement of a 27°41'19" angle?
Expert Solution & Answer
To determine
The complements of the angle 27o41'19".
Answer to Problem 1A
The complementary angle is
Explanation of Solution
The two angles complementing each other are called complementary angles. The sum of the two complementary angles is 90o.
The angle given is 27o41'19".
The complementary angle is
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Chapter 52 Solutions
EBK MATHEMATICS FOR MACHINE TECHNOLOGY
Ch. 52 - What is the complement of a 2741'19" angle?Ch. 52 - Express 721252 as decimal degrees. Round the...Ch. 52 - Prob. 3ACh. 52 - Solve for F in the proportion...Ch. 52 - Prob. 5ACh. 52 - Prob. 6ACh. 52 - Prob. 7ACh. 52 - Name each of the following angles in two...Ch. 52 - Identify each of the following angles as acute,...Ch. 52 - Prob. 10A
Ch. 52 - Prob. 11ACh. 52 - Solve the following exercises: Determine the...Ch. 52 - Determine the values of 2,3, and 4 for these given...Ch. 52 - Given: ABCD. Determine the values of 2 through 8...Ch. 52 - Given: Hole centerlines EFGH and MPKL. Determine...Ch. 52 - Given: Hole centrelines ABCD and EFGH . Determine...Ch. 52 - Given: ABCD,AEED. Determine the value of 2 and 3...Ch. 52 - Given: FHGSKM and FGHK . Determine the value of ...
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- 3) Find an equation for the parabola with a vertex at (1, 2) and focus at (1, 4). A) (x - 1)² = 8(y-2) C) (x - 1)² = -8(y - 2) B) (y - 2)² = -12(x − 1) - D) (y - 2)² = 12(x-1)arrow_forward2) Graph the equation. y² = 12x 5 10 -10 -5 5 + 10 xarrow_forward15) Solve the triangles if possible. B = 11°, b = 15.5, a = 40.62arrow_forward
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- 1) Find an equation of the parabola with a focus at (0, 4) and directrix the line y = -4, and state the two points that define the latus rectum. A) x² = 16y; latus rectum: (4, 8) and (-4,8) B) x² = 4y; latus rectum: (2, 4) and (-2, 4) C) x² = 16y; latus rectum: (8, 4) and (-8, 4) D) y² = 4x; latus rectum: (9, 2) and (-9, 2)arrow_forward4) A spotlight has a parabolic cross section that is 6 ft wide at the opening and 2.5 ft deep at the vertex. How far from the vertex is the focus? Round answer to two decimal places. A) 0.90 ft B) 0.21 ft C) 0.52 ft D) 0.26 ftarrow_forward5) Match the graph to its equation. 10+ -10 -5 5 + 10 x -10arrow_forward
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