Biological Science (7th Edition)
Biological Science (7th Edition)
7th Edition
ISBN: 9780134678320
Author: Scott Freeman, Kim Quillin, Lizabeth Allison, Michael Black, Greg Podgorski, Emily Taylor, Jeff Carmichael
Publisher: PEARSON
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Chapter 52, Problem 15PIAT
Summary Introduction

To review:

The observed relationship between increased forest fragmentation and increased incidence of Lyme disease.

Introduction:

Forest fragmentation is the process of division of large habitats into smaller, divided, and isolated fragmented areas. It lowers the quality of the forest. This results in the decline in the species richness in the fragments. The white-footed mice occupy a broad ecological niche, while opossums are absent from low-quality forest fragment.

Hypothesis proposed: B. burgdorferi is the bacterium that is transferred into the body of humans by the ticks. The bacterium is an endoparasite that lives inside the human body and causes Lyme disease. The newly hatched ticks do not harbor B. burgdorferi bacterium as they are killed by the host when they crawl onto the host organism, and if they are successful in harvesting the blood from their host, then they are generally not infected by B. burgdorferi. A bar diagram showing the proportion of larval ticks that fed and caused infection versus host species is given below:

Biological Science (7th Edition), Chapter 52, Problem 15PIAT

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After you feel comfortable with your counting method and identifying cells in the various stages of mitosis, use the four images below of whitefish blastula to count the cells in each stage until you reach 100 total cells, recording your data below in Data Table 1. (You may not need to use all four images. Stop counting when you reach 100 total cells.) After totaling the cells in each stage, calculate the percent of cells in each stage. (Divide total of stage by overall total of 100 and then multiply by 100 to obtain percentage.)   Data Table 1Stage    Totals    PercentInterphase        Mitosis:        Prophase        Metaphase        Anaphase        Telophase        Cytokinesis        Totals    100    100% To find the length of time whitefish blastula cells spend in each stage, multiply the percent (recorded as a decimal, in other words take the percent number and divide by 100) by 24 hours. (Example: If percent is 20%, then Time in Hours = .2 * 24 = 4.8) Record your data in Data…
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