Explanation Given information: The shaft rotates at 600 rpm. The radius of the fillet weld connecting the shafts is 0.18 in. Calculation: Determine the power transmitted ( P ) by the shaft using the relation: P = T ω (1) Here, the applied torque is T and the angular velocity of the shaft is ω . The expression for angular velocity of the shaft ( ω ) is shown below: ω = 2 π f (2) Here, the frequency of shaft’s rotation is f . Substitute 600 rev min for f in Equation (2). ω = 2 π ( 600 rev min ) = 2 π ( 600 rev min ) ( 1 min 60 sec ) = 20 π rad sec Substitute 30 hp for P and 20 π rad sec for ω in Equation (1). 30 hp = T ( 20 π rad sec ) 30 hp ( 550 ft ⋅ lb sec 1 hp ) = T ( 20 π rad sec ) T = 825 π lb ⋅ ft Let D be the larger diameter of the shaft, d be the smaller diameter of the shaft, and r be the radius at transition between the cross sections. The value of D is 2.5 in., d is 2 in., and r is 0.18 in. Find the value of D d as shown below: Substitute 2.5 in. for D and 2 in. for d . D d = 2.5 in . 2 in . = 1.25 Find the value of r d as shown below: Substitute 0.18 in. for r and 2 in. for d . r d = 0.18 in

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ISBN: 2818440034374

Author: HIBBELER

Publisher: PEARSON

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Chapter 5.10, Problem 5.123P

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The maximum shear stress in the shaft.

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Chapter 5.10, Problem 5.122P

Chapter 5.10, Problem 5.124P

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The maximum shear stress in the shaft.

Solution Summary: The author calculates the maximum shear stress in the shaft using the relation: P=Tomega .

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The maximum shear stress in the shaft.

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