The manager of a cable company that offers both digital TV and high-speed Internet is trying to arrange his service calls efficiently. He wants to divide the people awaiting service into groups based on whether they need TV or Internet service so that his techs can concentrate on one type of service each day. If there are 40 people waiting for TV service and 32 waiting for Internet service, and he wants to schedule the same number of visits each day, what’s the greatest number of visits he can schedule each day?
The manager of a cable company that offers both digital TV and high-speed Internet is trying to arrange his service calls efficiently. He wants to divide the people awaiting service into groups based on whether they need TV or Internet service so that his techs can concentrate on one type of service each day. If there are 40 people waiting for TV service and 32 waiting for Internet service, and he wants to schedule the same number of visits each day, what’s the greatest number of visits he can schedule each day?
Solution Summary: The author explains that the greatest number of visits the manager can schedule per day is 8 visits. The common factors of 40 and 32 are 2, 2 and 2.
The manager of a cable company that offers both digital TV and high-speed Internet is trying to arrange his service calls efficiently. He wants to divide the people awaiting service into groups based on whether they need TV or Internet service so that his techs can concentrate on one type of service each day. If there are 40 people waiting for TV service and 32 waiting for Internet service, and he wants to schedule the same number of visits each day, what’s the greatest number of visits he can schedule each day?
Write an equation for the polynomial graphed below
5+
4
3
1
+
+
+
-5-4-3-2
1
13 4 5
-1
-2
-3
-4
-5+
4 5
Q
y(x) =
1. Name the ongiewing)
2. Name five pairs of supple
3 27 and 19 form a
angles
210 and 21 are complementary angies
4. m210=32 mal!=
5 mc11-72 m10=
6 m210-4x mc11=2x x=
7 m210=x m 11 =x+20; x=
12 and 213 are supplementary angles
8 ma 12 2y m13-3y-15 y=
9 m 12-y+10 m13-3y+ 10: y=
10. The measure of 212 is five times the measure of 13. Find the
213 and 214 are complementary angles, and
14 and 15 are supplementary angies
11 mc13 47 m/14-
12 m 14-78 m13-
m215-
m15
13 m15-135 m. 13-
m.14
3. Solve the inequality, and give your answer in interval notation.
-
(x − 4)³ (x + 1) ≥ 0
University Calculus: Early Transcendentals (4th Edition)
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