Explanation Given: The sigma notation of f ∑ k = 1 4 f ( 2 + k ) ⋅ 1 The length of the subintervals Δ x = 1 . Formula used: Let [ a , b ] be the interval where a and b are unknowns. The right Riemann sum for the function f on the interval [ a , b ] with n subintervals as follows. ∑ k = 1 n f ( x k * ) Δ x = ∑ k = 1 n f [ a + k Δ x ] Δ x . Substitute ∑ k = 1 n f ( x k * ) Δ x = ∑ k = 1 4 f ( 2 + k ) ⋅ 1 in above equation. ∑ k = 1 n f [ a + k Δ x ] Δ x = ∑ k = 1 4 f ( 2 + k ) ⋅ 1

Calculus: Early Transcendentals (2nd Edition)

2nd Edition

ISBN: 9780321947345

Author: William L. Briggs, Lyle Cochran, Bernard Gillett

Publisher: PEARSON

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Chapter 5.1, Problem 60E

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To fill: ∑k=14f(2+k)⋅1 is a Riemann sum for f on the interval [ , ] with

n= __.

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Chapter 5.1, Problem 59E

Chapter 5.1, Problem 61E

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∑ k = 1 4 f ( 2 + k ) ⋅ 1 is a Riemann sum for f on the interval [ , ] with n = __.

Solution Summary: The author explains the sigma notation of f and the right Riemann sum for the function.

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To fill: ∑k=14f(2+k)⋅1 is a Riemann sum for f on the interval [ , ] with

n= __.

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Chapter 5 Solutions

∑ k = 1 4 f ( 2 + k ) ⋅ 1 is a ______ Riemann sum for f on the interval [ __, __ ] with n = ________.

Solution Summary: The author explains the sigma notation of f and the right Riemann sum for the function.

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To fill: ∑k=14f(2+k)⋅1 is a ______ Riemann sum for f on the interval [ __, __ ] with n= ________.

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Chapter 5 Solutions

∑ k = 1 4 f ( 2 + k ) ⋅ 1 is a Riemann sum for f on the interval [ , ] with n = __.

To fill: ∑k=14f(2+k)⋅1 is a Riemann sum for f on the interval [ , ] with

n= __.